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Ksju [112]
2 years ago
11

Solve for the roots: x3-2x2+3x-6

Mathematics
2 answers:
Levart [38]2 years ago
7 0

x^3 - 2x^2+ 3x - 6 = 0

Hint: Solve by grouping.

forsale [732]2 years ago
4 0

Answer:

x = 2, i\sqrt[]{3},  -i \sqrt{3}

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2 years ago
Please help me if you can. Please also write how you got the answer thank you.
vaieri [72.5K]

Answer:

The three numbers are 341, 342, and 343

Step-by-step explanation:

We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1026. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1026

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1026

3X + 3 = 1026

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3X = 1023

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Which means that the first number is 341, the second number is 341 + 1 and the third number is 341 + 2. Therefore, three consecutive integers that add up to 1026 are 341, 342, and 343.

341 + 342 + 343 = 1026

We know our answer is correct because 341 + 342 + 343 equals 1026 as displayed above.

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