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3 years ago

Solve the equation. 2x + 12 = 2(x + 6)

Mathematics

1 answer:

Vilka [71]3 years ago

5 0

Answer:

Infinitely many solutions

Step-by-step explanation:

Step 1- Distribute into the parenthesis.

2x+12= 2(x+6)

2x+12= (2)x+(2)6

Step 2- Multiply

2x+12= 2x+12

Since they are equal, they are infinite.

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According to a survey of workers, 5/25 of them walk to work, 1/25 bike, 4/25 carpool, and 15/25 drive alone. What percent of wor

KATRIN_1 [288]

Answer: 24%

Step-by-step explanation:

First add up the proportion of people who walk to work and those who bike as well. This will show the proportion of people who walk or bike to work.

This is:

= 5/25 + 1/25

= 6/25

Then convert this to a percentage:

= 6/25 * 100

= 24%

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3 years ago

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Leya [2.2K]

Answer:

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Step-by-step explanation:

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2 years ago

5x+3(3x−43)=............

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3 years ago

Read 2 more answers

How many variable terms are in the expression 3x^y + 5x^ - 4y + z + 9?

Bess [88]

The number of variables in the problem is 3

8 0

3 years ago

Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

$r(r-5)(r-4)=0$

now, we can set them equal

$r=0$

$r-5=0$

$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

4 0

3 years ago