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Vera_Pavlovna [14]
4 years ago
15

Sam's teacher is trying to model the day/night cycle on Earth. One student holds a large yellow ball to represent the Sun. Anoth

er student holds a smaller brown ball to represent Earth.
Chemistry
1 answer:
STatiana [176]4 years ago
6 0
What’s the question here
You might be interested in
Please help!
Anna71 [15]

The compound that is most likely present when treated with bromine and the sample absorbs the red bromine color is ; Cycloheptene

<h3>What is cycloheptene </h3>

Cycloheptene is an unsaturated colorless oily liquid which is insoluble in water it absorbs Bromine when used in performing unsaturation test due it unsaturated nature.

The red bromine color will be absorbed when used to treat Cycloheptene but will not be absorbed when used to treat cycloheptane due to its saturated nature.  

Hence we can conclude that the compound that is present is Cycloheptene.

Learn more about Unsaturation : brainly.com/question/561845

5 0
3 years ago
What is the maximum number of electrons that an L shell may contain?
kirill [66]

Answer:

Eight

Explanation:

The L shell only holds eight electrons.

5 0
3 years ago
Read 2 more answers
Find the molar mass of H20. _______ grams per mole
Tpy6a [65]
It would be: 1 * 2 + 16 = 2 + 16 = 18

In short, Your Answer would be Option B

Hope this helps!
4 0
3 years ago
Consider the reaction for the dissolution of solid magnesium hydroxide.
sp2606 [1]

Answer:

Molar solubility is 1.12x10⁻⁴M

Explanation:

The dissolution of magnesium hydroxide is:

Mg(OH)₂(s) ⇄ Mg²⁺ + 2OH⁻

The molar solubility represents the moles of the solid that the solution can dissolve, that could be written as:

Mg(OH)₂(s) ⇄ X + 2X

<em>Where X is solubility.</em>

<em />

If you obtained a [OH⁻] = 2.24x10⁻⁴M and you know [OH⁻] = 2X:

2X = 2.24x10⁻⁴M

X = 2.24x10⁻⁴M/2

X =1.12x10⁻⁴M

<h3>Molar solubility is 1.12x10⁻⁴M</h3>
4 0
3 years ago
in a sample of silcon 92.21% of the atoms have a mass of 27.98 amu, 4.70% have a mass of 28.98 amu and 3.09% have a mass of 29.9
oksano4ka [1.4K]

Answer: 28.1 amu

Explanation:

Mass of isotope 1 = 27.98 amu

% abundance of isotope 1 = 92.21% = \frac{92.21}{100}=0.9221

Mass of isotope 2 = 28.98 amu

% abundance of isotope 2 = 4.70% = \frac{4.70}{100}=0.047

Mass of isotope 3 = 29.97 amu

% abundance of isotope 2 = 3.09% = \frac{3.09}{100}=0.0309

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(27.98 )\times 0.922+(28.98)\times 0.047+(29.97)\times 0.0309]

A=28.1amu

Therefore, the average atomic mass of silicon is 28.1 amu

5 0
3 years ago
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