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Luden [163]
2 years ago
10

Which of the following is the correct rank of increasing electron affinities (from less exothermic to more exothermic)? Select t

he correct answer below: Cs
Chemistry
1 answer:
Lena [83]2 years ago
8 0

The question is incomplete, the complete question is ;

Which of the following is the correct rank of increasing electron affinities (from less exothermic to more exothermic)? Select the correct answer below: O Cs <K<Na <Li O Li< Na <K <Cs O Na <Li<K <Cs OK<Cs < Li< Na

Answer:

Cs< K<Na<Li

Explanation:

The electron affinity is defined as the energy released when a neutral gaseous atom accepts an electron to create a gaseous negative ion. This reaction is exothermic and leads to the evolution of heat.

When an electron is added to a metal, large energy is required since metals are usually electro positive. Electron affinity decreases down the group since electrons enter into higher energy levels further away from the nucleus. They experience lesser nuclear attraction.

This is clearly evidenced in the sharp decrease in the electron affinity of group one elements from lithium to caesium. The electron affinity of lithium is 60Kjmol-1 but decreases steadily down the group to a value of 46KJmol-1 for caesium. This explains the order chosen in the answer.

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A 6.68-g aqueous solution of isopropyl alcohol contains 3.97 g of isopropyl alcohol. What is the mass percentage of isopropyl al
Sphinxa [80]

Answer : The mass percentage of isopropyl alcohol in the solution is, 59.4 %

Explanation :

To calculate the mass percentage of isopropyl alcohol in the solution, we use the equation:

\text{Mass percent of isopropyl alcohol}=\frac{\text{Mass of isopropyl alcohol}}{\text{Mass of isopropyl alcohol solution}}\times 100

Mass of isopropyl alcohol = 6.68 g

Mass of isopropyl alcohol solution = 3.97 g

Putting values in above equation, we get:

\text{Mass percent of isopropyl alcohol}=\frac{3.97g}{6.68g}\times 100=59.4\%

Thus, the mass percentage of isopropyl alcohol in the solution is, 59.4 %

6 0
3 years ago
What pressure (in atm) will 0.44 moles of co2 exert in a 2.6 l container at 25°c?
Lilit [14]
We can use the ideal gas law equation to find the pressure 
PV = nRTwhere 
P - pressure 
V - volume  - 2.6 x 10⁻³ m³ 
n - number of moles - 0.44 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values into the equation,
P x 2.6 x 10⁻³ m³  = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 419 281.41 Pa
101 325 Pa is equivalent to 1 atm 
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Pressure is 4.13 atm
6 0
3 years ago
6.0 mol NaOH reacts with
kodGreya [7K]

2 moles of Na3PO4 form from 6.0 mol NaOH. Details about stoichiometry can be found below.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated stoichiometrically as follows:

3NaOH + H3PO4 → 3H₂O + Na3PO4

According to this equation,

3 moles of NaOH produces 1 mole of Na3PO4

This means that 6 moles of NaOH will produce 6/3 = 2 moles of Na3PO4

Therefore, 2 moles of Na3PO4 form from 6.0 mol NaOH.

Learn more about stoichiometry at: brainly.com/question/9743981

#SPJ1

7 0
1 year ago
Which of the following is an example of a physical property?*
MariettaO [177]

Answer: The mass

Explanation: ability to rust, flammability, and ability to combust are chemical properties.

3 0
3 years ago
gThe atomic radii of a divalent cation and a monovalent anion are 0.085 nm and 0.125 nm, respectively. (a) Calculate the force o
frozen [14]

Answer:

1.05 × 10⁻⁸ N

Explanation:

Using Coulomb's law

F force of attraction between them = k \frac{q^{2} }{r^{2} } = k \frac{z1z2q^{2} }{r^{2} }

K coulomb constant = 8.99 × 10⁹ N m²C⁻²

Z₁ = + 2 ( valency electron)

Z₂ = -1 ( valency electron)

r is the distance between then since they just touch one another = 0.085 nm + 0.125 nm = 0.21 nm = 0.21 × 10⁻⁹ m

q charge = 1.602 × 10⁻¹⁹ C of an electron

F = ( 2 × 1 × 8.99 × 10⁹ N m²C⁻² × (1.602 × 10⁻¹⁹ C)² / ( 0.21 × 10⁻⁹ m )² = 1046.34 × 10 ⁻¹¹ = 1.05 × 10⁻⁸ N

6 0
3 years ago
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