Answer : The mass percentage of isopropyl alcohol in the solution is, 59.4 %
Explanation :
To calculate the mass percentage of isopropyl alcohol in the solution, we use the equation:

Mass of isopropyl alcohol = 6.68 g
Mass of isopropyl alcohol solution = 3.97 g
Putting values in above equation, we get:

Thus, the mass percentage of isopropyl alcohol in the solution is, 59.4 %
We can use the ideal gas law equation to find the pressure
PV = nRTwhere
P - pressure
V - volume - 2.6 x 10⁻³ m³
n - number of moles - 0.44 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values into the equation,
P x 2.6 x 10⁻³ m³ = 0.44 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
P = 419 281.41 Pa
101 325 Pa is equivalent to 1 atm
Therefore 419 281.41 Pa - 1/ 101 325 x 419 281.41 = 4.13 atm
Pressure is 4.13 atm
2 moles of Na3PO4 form from 6.0 mol NaOH. Details about stoichiometry can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated stoichiometrically as follows:
3NaOH + H3PO4 → 3H₂O + Na3PO4
According to this equation,
3 moles of NaOH produces 1 mole of Na3PO4
This means that 6 moles of NaOH will produce 6/3 = 2 moles of Na3PO4
Therefore, 2 moles of Na3PO4 form from 6.0 mol NaOH.
Learn more about stoichiometry at: brainly.com/question/9743981
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Answer: The mass
Explanation: ability to rust, flammability, and ability to combust are chemical properties.
Answer:
1.05 × 10⁻⁸ N
Explanation:
Using Coulomb's law
F force of attraction between them = k
= k 
K coulomb constant = 8.99 × 10⁹ N m²C⁻²
Z₁ = + 2 ( valency electron)
Z₂ = -1 ( valency electron)
r is the distance between then since they just touch one another = 0.085 nm + 0.125 nm = 0.21 nm = 0.21 × 10⁻⁹ m
q charge = 1.602 × 10⁻¹⁹ C of an electron
F = ( 2 × 1 × 8.99 × 10⁹ N m²C⁻² × (1.602 × 10⁻¹⁹ C)² / ( 0.21 × 10⁻⁹ m )² = 1046.34 × 10 ⁻¹¹ = 1.05 × 10⁻⁸ N