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Likurg_2 [28]
3 years ago
12

Amelia knits 1/10 of a scarf in 48 minutes. What fraction of a scarf can Amelia knit in 1 hour? Show work

Mathematics
1 answer:
satela [25.4K]3 years ago
3 0

That's

\dfrac{60}{48} \times \dfrac{1}{10} = \dfrac{1}{8}

Answer: 1/8

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On the blueprint of a house, 38 millimeters represents 6 meters. the length of the living room is 57 millimeters on the blueprin
Pie
For this case we can make the following rule of three:
 38 milimeters ---------> 6 meters
 57 milimeters ---------> x
 Clearing x we have:
 x = (57/38) * (6)
 x = 9 meters
 Answer:
 
the current length of the living room is:
 
x = 9 meters
3 0
3 years ago
sarah spent a total of 10 on oranges and apples at the supet market. if she spent 3 dollars less for oranges than she did on app
beks73 [17]

Let's write 2 equations from the two statements given.

<em>Sarah spent 10 dollars on both oranges and apples</em>

<em />

Let the price of oranges be "x" and price of apples be "y", thus we can write:

x+y=10

Oranges cost 3 less than apples, thus we can say:

y-3=x

We can substitute this into the first equation and solve for y:

\begin{gathered} x+y=10 \\ y-3+y=10 \\ 2y=10+3 \\ 2y=13 \\ y=\frac{13}{2} \\ y=6.5 \end{gathered}

Thus, let's solve for x now,

\begin{gathered} x=y-3 \\ x=6.5-3 \\ x=3.5 \end{gathered}

We want the price of oranges (x), thus,

<em>Price of Oranges = $3.50</em>

3 0
11 months ago
What are the solutions of the following equation?
noname [10]

Answer:

D. x = 7 and x = 14

Step-by-step explanation:

this is a quadratic equation, so use the quadratic formula: (-b+-√b^2-4ac) / 2a for ax^2+bx+c=0

7 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
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