Answer:
A y-intercept is were your line (on a graph) starts.
Using the given information, the coordinates of B are (-7, 4)
<h3>Midpoint of a Line </h3>
From the question, we are to determine the coordinates of B.
Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is
((x₁+x₂)/2, (y₁+y₂)/2)
From the given information,
The midpoint of AB is M(-3, 0)
and
The coordinates of A are (1,-4)
Let the coordinates of B be (x₁, y₁)
Then,
-3 = (1 + x₁)/2
-6 = 1 + x₁
x₁ = -6 -1
x₁ = -7
Also,
0 = (-4 + y₁)/2
0 = -4 + y₁
y₁ = 0 + 4
y₁ = 4
Hence, the coordinates of B are (-7, 4)
Learn more on Midpoint of a line here: brainly.com/question/18315903
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By the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
<h3>How to find the solution of quadratic equation</h3>
Herein we have a <em>quadratic</em> equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the <em>quadratic</em> formula:
x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c) (1)
If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:
x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]
x = - 6 ± (1 / 2) · 12
x = - 6 ± 6
Then, by the quadratic formula, the <em>solution</em> set of the <em>quadratic</em> equation is formed by two <em>real</em> roots: x₁ = 0 and x₂ = - 12.
To learn more on quadratic equations: brainly.com/question/1863222
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Answer:
I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.
Answer:
350-60
Hope this helps. Have a great day:)
