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Tema [17]
3 years ago
11

Find the lateral and surface area of each figure. round to the nearest tenth if necessary​

Mathematics
1 answer:
galben [10]3 years ago
4 0

Answer:

\large\boxed{7.\ L.A.\approx7771.5\ mm^2}\\\\\boxed{8.\ L.A.\approx621.7\ in^2}\\\\\boxed{9.\ L.A.\approx628\ m^2}

Step-by-step explanation:

The formula of a lateral surface of a cone:

L.S.=\pi rs

r - radius

s - slant height

====================================

\pi\approx3.14

7.\\r=45mm,\ s=55mm\\\\L.A.=\pi(45)(55)=2475\pi\ mm^2\\\\L.A.\approx2475\cdot3.14=7771.5\ mm^3

8.\\r=11\ in,\ s=18\in\\\\L.A.=\pi(11)(18)=198\pi\ in^2\\\\L.A.\approx198\cdot3.14=621.72\ in^2\approx621.7\ in^2

9.\\r=10m,\ s=20m\\\\L.A.=\pi(10)(20)=200\pi\ m^2\\\\L.A.\approx200\cdot3.14=628\ in^2

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10

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Solve for w. <br> 5w+9z=2z+3w
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3 years ago
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
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Answer:

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If 1 box has 12 candies.

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