When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
Answer:
21.7391%
Step-by-step explanation:
21800/1002.80
If f(x) = 2x - 5 and g(x) = x + 52, then f(g(x)) can be deduced by placing g(x) in the spot of x in the f(x) equation as follows:
f(g(x)) = 2(g(x)) - 5
Since we know g(x) = x + 52, let's plug it in:
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
Answer:
238
Step-by-step explanation:
299+428-62-106-126-195
727-62-106-126-195
665-106-126-195
559-126-195
433-195
238
Answer:
x = X + 33 (I am guessing "x" and "X" are not the same. "x" is a variable and "X" is a constant.)
Step-by-step explanation:
31 - X + (2x+1) = x - 1
or, 2x+1 = x - 1 - 31 + X
or, 2x - x = -1 -31 + X -1
or, x = -2 -31 + X
or, x = X - 33
