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3 years ago

2,381,579 expanded form

Mathematics

2 answers:

Setler [38]3 years ago

8 0

2,000,000 + 300,000 + 80,000 + 1,000 + 500 + 70 + 9

o-na [289]3 years ago

7 0

2,000,000+300,000+80,000+1,000+500+70+9 is 2,381,579 in expanded form.

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The number of measles cases increased 13.6 % to 57 cases this year, what was the number of cases prior to the increase? (Express

ELEN [110]

Answer:

The number of cases prior to the increase is 50.

Step-by-step explanation:

It is given that the number of measles cases increased by 13.6% and the number of cases after increase is 57.

We need to find the number of cases prior to the increase.

Let x be the number of cases prior to the increase.

x + 13.6% of x = 57

$x+x\times \frac{13.6}{100}=57$

$x+0.136x=57$

$1.136x=57$

Divide both the sides by 1.136.

$\frac{1.136x}{1.136}=\frac{57}{1.136}$

$x=50.176$

$x\approx 50$

Therefore the number of cases prior to the increase is 50.

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3 years ago

Please help me with this I’ll give brainlist

bezimeni [28]

Answer:

Can you give me the name of your assignment paper please?

Step-by-step explanation:

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3 years ago

Indicate the equation of the given line in standard form.The line containing the median of the trapezoid whose vertices are R(-1

maxonik [38]

RS => y - 5 = (8 - 5)/(1 - (-1)) (x - (-1))
y - 5 = 3/2 (x + 1) => slope = 3/2
ST => y - 8 = (-2 - 8)/(7 - 1) (x - 1)
y - 8 = -10/6 (x - 1) = -5/3 (x - 1) => slope = -5/3
TU => y - (-2) = (0 - (-2))/(2 - 7) (x - 7)
y + 2 = 2/5(x - 7) => slope = 2/5
UR => y = 5/(-1 - 2) (x - 2)
y = -5/3 (x - 2) => slope = -5/3

The median is the line joining the midpoints of the non-parallel sides.
Midpoint of RS = ((-1 + 1)/2, (5 + 8)/2) = (0, 13/2)
Midpoint of TU = ((7 + 2)/2, -2/2) = (9/2, -1)

Equation of the line joining (0, 13/2) and (9/2, -1) is given by y - 13/2 = (-1 - 13/2)/(9/2) x
y - 13/2 = (-15/2)/(9/2) x
y - 13/2 = -15/9x
18y - 117 = -30x
30x + 18y = 117

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3 years ago

What is the distance between the following points?

likoan [24]

Answer:

11.

Step-by-step explanation:

9 right, and 2 up

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3 years ago

A park is 4 times as it is wide. If the distance around the park is 12.5 kilometers what is the area of the park

MaRussiya [10]

Answer:

6.25 km

Step-by-step explanation:

Here is the correct question: A park is 4 times as long as it is wide. If the distance around the park is 12.5 kilometers, what is the area of the park?

Given: Perimeter (Distance) of the park= 12.5 km

Considering park is in rectangular shape.

Let the width of park be x

∴ as given length will be 4x.

Formula for perimeter of rectangle = $2\times (length + width)$