1) C(2
2) A(-4
3) B(4+(2+1)=4+2)+1
4) D(3(2x4)=(3x2)4
5) A(5+6=6+5
6) C(12x1=1x12
7) D(Exponents
8) A(addition and subtraction
9) A(55
10) B(19
We know that
<span>sec (theta)=1/cos (theta)
</span><span>cot (theta) = -2
cot (theta)=cos (theta)/sin (theta)
</span>cos (theta)/sin (theta)=-2----> squaring-----> cos² (theta)/sin² (theta)=4
<span>remember that
sin</span>²(theta)+cos²(theta)=1
sin² (theta)=1-cos² (theta)
substitute
cos² (theta)/[1-cos² (theta)]=4
cos² (theta)=4*[1-cos² (theta)]-----> cos² (theta)+4 cos² (theta)=4
5*cos² (theta)=4-----> cos² (theta)=4/5----> cos (theta)=2/√5
cos (theta)=(2√5)/5-----> is positive (IV quadrant)
sec (theta)=1/cos (theta)----> √5/2
the answer is
sec (theta)=√5/2
You wouldnt get any solutions as if you substituted them into each other you would get:
-3x - 6 = -3x + 7
the -3x cancel eachother out so you end up with
-6 = 7 which isnt true
60 sec = 1 min
176 x 60 = 10, 560
Answer:
D) y = -4x + 5
Step-by-step explanation:
We know a point and a slope. The point is a special point. It is the y intercept because x = 0. We can use the equation for a line in slope intercept form
y= mx+b
where m is the slope = -4
and b is the y intercept = 5
y = -4x+5
