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Lunna [17]
2 years ago
10

What is the unit length of a'b'

Mathematics
1 answer:
ladessa [460]2 years ago
8 0
5
is thr correct answer

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Please help and thank you
makvit [3.9K]

Answer:

  • f(x) should be reflected across the y-axis
  • f(x) should be horizontally translated

Step-by-step explanation:

We imagine Jenessa's elevation plots might look like those in the attachment. The red graph would be of f(x) when preparing for the race, and the green graph would be f(x) during the race.

The green graph is not a simple reflection or translation of the red graph, but is a combination of both. Thus, the two answer choices shown above are both applicable.

8 0
2 years ago
What is the solution set for 2x + 2 = 6, given the replacement set {1, 2, 3, 4}?
leva [86]
2x+2=6
2x=4
x=2

Hope this helps :)
7 0
3 years ago
Read 2 more answers
Simplify the following expression.
o-na [289]

Answer:

i dont know what you mean but

3x(4x-3) simplified is 12x - 4 or 12x+(-4)

3 0
3 years ago
Question in image again
Reil [10]
16in I believe irdk
Hope it helped..
7 0
2 years ago
Read 2 more answers
Solve the following equation:
Rama09 [41]

Complete the square.

z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0

\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4

Use de Moivre's theorem to compute the square roots of the right side.

w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)

\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2

Now, taking square roots on both sides, we have

z^2 + \dfrac12 = \pm w^{1/2}

z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2

Use de Moivre's theorem again to take square roots on both sides.

w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)

\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}

w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)

\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}

3 0
1 year ago
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