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3 years ago

0.06 0.6 6 60 600 6000

Mathematics

1 answer:

Monica [59]3 years ago

5 0

6,000
60,000
600,000
and so on and so forth

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A movie theater sends out a coupon for 70% off the price off a ticket. a) Write an equation for the situation, where y is the pr

sergey [27]

Equation 1
y=x-0.7

equation 2
x=y+0.7

4 0

4 years ago

Read 2 more answers

I need help pleaseeeeeeeee

oee [108]

Answer:

-2x

Step-by-step explanation:

x^2-10x+24

-20x+24

x-6= -6x

4x-6x

4-6=-2

bring down the x and you get -2x

hope this helps

4 0

4 years ago

Write a variable expression for this amount a number x decreased by 6

ANEK [815]

I'm not exactly sure what you're asking but I'll give it a go.
A = x -6

6 0

3 years ago

Read 2 more answers

National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea

kirill115 [55]

Answer:

The required expression is $y=250,000-24,000 t$

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m= $\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}$

Rate of change=m= $\frac{Rise}{Run}=\frac{-240,000}{10}$

Rate of change=m= $\frac{Rise}{Run}=-24,000$

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

$(y-250,000)=-24,000(t-0)$

$y-250,000=-24,000 t$

$y=250,000-24,000 t$

Hence, the required expression is $y=250,000-24,000 t$

6 0

3 years ago

Given the following probability distribution, what is the expected value of the random variable X? X P(X) 100 .10 150 .20 200 .3

Mekhanik [1.2K]

Answer:

d) 205

Step-by-step explanation:

Step(i):-

x : 100 150 200 250 300

p(X=x) : 0.10 0.20 0.30 0.30 0.10

Step(ii):-

Let 'X' be the discrete random variable

Expected value of the random variable

E(X) = ∑ x P(X=x)

= 100 X 0.10 + 150 X 0.20 + 200 X 0.30 +250 X 0.30 + 300 X 0.10

= 205

Final answer:-

The expected value E(X) = 205

5 0

4 years ago