Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
The best prediction of the height of a student with an arm span of 143 cm is 143 cm
Step-by-step explanation:
The missing graph is attached
The graph below shows the heights and arm spans of students in
a classroom
- The x-axis represents the height in cm
- The y-axis represents the arm span in cm
We need to find the height of a student with an arm span of 143 cm
∵ The graph does not contain the value of the given arm span
∴ We will use the line best fit (sold line in the attached graph) to find
the best predication of the height
∵ The line passes through points (150 , 150) and (160 , 160)
- The x-coordinates are equal the y-coordinate
∴ The equation of the line is y = x
∵ The arm span of a student is 143 cm
∵ y represents the arm span of a student
∴ y = 143
- Substitute the value of y in the equation of the line best fit
∵ y = x
∴ 143 = x
∵ x represents the height of a student
∴ The height of the student is 143 cm
The best prediction of the height of a student with an arm span of 143 cm is 143 cm
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Answer:
B: 8:14
Step-by-step explanation:
Its because there are 8 yellow one out of 14 blue ones pls mark me brainliest
Answer:
t = 9
Step-by-step explanation:
<em>-t = 9(t - 10)</em>
First, distribute the 9.
<em>-t = 9t - 90</em>
Next, add subtract 9t from both sides.
<em>(-t) - 9t = (9t - 90) - 9t</em>
<em>-10t = -90</em>
Divide both sides by -10. When you divide a negative by another negative, they cancel each other out.
<em>(-10t)/-10 = (-90)/(-10)</em>
<em>t = 9</em>