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Sveta_85 [38]
2 years ago
15

(3.6x10^8) divided by (9x10^3)

Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

Answer:

Step-by-step explanation:

The answer is 40000

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Please help me thankss
Fantom [35]

Answer:

the answer is 45

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Evaluate the limit as x approaches 0 of (1 - x^(sin(x)))/(x*log(x))
e-lub [12.9K]
sin~ x \approx x ~ ~\sf{as}~~ x \rightarrow 0

We can replace sin x with x anywhere in the limit as long as x approaches 0.

Also,

\large  \lim_{ x \to 0  } ~  x^x = 1

I will make the assumption that <span>log(x)=ln(x)</span><span>.

The limit result can be proven if the base of </span><span>log(x)</span><span> is 10. 
</span>
\large \lim_{x \to 0^{+}} \frac{1- x^{\sin x} }{x  \log x }  \\~\\  \large = \lim_{x \to 0^{+}} \frac{1- x^{\sin x} }{ \log( x^x)  }   \\~\\  \large = \lim_{x \to 0^{+}} \frac{1- x^{x} }{ \log( x^x)  }  ~~ \normalsize{\text{ substituting x for sin x } } \\~\\   \large  = \frac{\lim_{x \to 0^{+}} (1) - \lim_{x \to 0^{+}} \left( x^{x}\right) }{ \log(  \lim_{x \to 0^{+}}x^x)  } = \frac{1-1}{\log(1)}   = \frac{0}{0}

We get the indeterminate form 0/0, so we have to use <span>Lhopitals rule 

</span>\large \lim_{x \to 0^{+}} \frac{1- x^{x} }{ \log( x^x)  } =_{LH} \lim_{x \to 0^{+}} \frac{0 -x^x( 1 + \log (x)) }{1 + \log (x)  }   \\ = \large \lim_{x \to 0^{+}} (-x^x) = \large - \lim_{x \to 0^{+}} (x^x) = -1
<span>
Therefore,

</span>\large \lim_{x \to 0^{+}} \frac{1- x^{\sin x} }{x  \log x }  =\boxed{ -1}<span>
</span>
3 0
2 years ago
Heather had $26 to spend on twelve cupcakes. After buying them,
grandymaker [24]

Answer:

$1.41

Step 1:

Subtract 9 from 26.

26 - 9 = 17.

Step 2:

Divide 17 by 12.

17 ÷ 12 = 1.4166...

The answer is $1.41. Hope it helps!

5 0
3 years ago
Find an equation of the line perpendicular to the graph of 10x - 5y = 8 that passes through the point at (-4, 7)
vladimir2022 [97]
We need to swap the numerator and denominator, and change the sign of one of them to get a perpendicular slope.5x + 10y = c. Now subtract the point.
5(-4) + 10(7) = -20 + 70 = 50 = c 
5x + 10y = 50 is an equation. If we want, we can divide everything by 5 to get x + 2y = 10.The more usual way to do these is put the equation in slope-intercept form by solving for y. 10x-5y=8 -5y = -10x + 8 y = 2x - 8/5 Now you have the slope of the original line, 2. Any line perpendicular to this one must have a slope that is the negative reciprocal of this one, -1/2 So this new line must be y = -1/2 x + c .Now subtract in point to solve for c.
7 = (-1/2)(-4) + c 7 = 2+c 
5 = c 
y = -1/2 x + 5 
The first time we solved we got this. 
x + 2y = 10 but, if we divide everything by 2, we get 1/2 x + y = 5 So... subtract 1/2 x from both sides and you have identical equations. So the two are equivalent. The answer is y = -1/2 x + 5 
Hope this helped!

5 0
3 years ago
When adding two numbers, such as 123 and 423, care is taken to first line them up and then add like digits. How does expanding t
zavuch27 [327]
Think of 10^2, 10^1, and 10^0 as x^2, x^1, and x^0.
When you add polynomials, you can only combine like terms.
When you add expanded numbers, you can only combine like powers of 10.

123 + 423 =

= (100 + 20 + 3) + (400 + 20 + 3)

= (1 * 10^2 + 2 * 10^1 + 3 * 10^0) + (4 * 10^2 + 2 * 10^1 + 3 * 10^0)

= (1 * 10^2 + 4 * 10^2) + (2 * 10^1 + 2 * 10^1) + (3 * 10^0 + 3 * 10^0)

= 5 * 10^2 + 4 * 10^1 + 6 * 10^0

= 500 + 40 + 6

= 546
7 0
2 years ago
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