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Nuetrik [128]
3 years ago
13

4 NH3 + 6 NO → 5 N2 + 6 H2O. How many moles of NO are required to completely react with 2.45 mol NH3? Show all of your work as w

ell as the answer with the proper units.
Chemistry
2 answers:
GalinKa [24]3 years ago
7 0
6 mol NO - 4 mol NH₃
x mol NO - 2.45 mol NH₃

x=2.45*6/4=3.675≈3.68 mol
Cerrena [4.2K]3 years ago
4 0

Answer:

There are required 3.68 moles of NO

Explanation:

Stoichiometry allow us to calculate quantities of reactants or products using the relationship established in a chemical reaction. In every chemical reaction the amount of mass of the reactants must be equal to the mass of the products, this is called <em>the law of conservation of mass.</em>

This equation says that 4 moles of NH₃ react with 6 moles of NO to produce 5 moles of N₂ and 6 moles of H₂0.

So having established the relationship between NH₃ and NO now we can calculate how many moles of NO are required to react with 2.45 moles of NH₃ by doing a simple calculation.

4 mol NH₃ → 6 mol No

2.45 mol NH₃→ X= ?

X= 2.45mol · 6 mol ÷ 4 mol = 3.68 mol

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