Question

4 NH3 + 6 NO → 5 N2 + 6 H2O. How many moles of NO are required to completely react with 2.45 mol NH3? Show all of your work as well as the answer with the proper units.

Answer 1

6 mol NO - 4 mol NH₃
x mol NO - 2.45 mol NH₃

x=2.45*6/4=3.675≈3.68 mol

Answer 2

Answer:

There are required 3.68 moles of NO

Explanation:

Stoichiometry allow us to calculate quantities of reactants or products using the relationship established in a chemical reaction. In every chemical reaction the amount of mass of the reactants must be equal to the mass of the products, this is called the law of conservation of mass.

This equation says that 4 moles of NH₃ react with 6 moles of NO to produce 5 moles of N₂ and 6 moles of H₂0.

So having established the relationship between NH₃ and NO now we can calculate how many moles of NO are required to react with 2.45 moles of NH₃ by doing a simple calculation.

4 mol NH₃ → 6 mol No

2.45 mol NH₃→ X= ?

X= 2.45mol · 6 mol ÷ 4 mol = 3.68 mol