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3 years ago

What does the kinetic theory state about the relationship between the speed and temperature of gas molecules?

1 answer:

5 0

The kinetic theory state about the relationship between the speed and temperature of gas molecules "As the temperature increases, the speed of gas molecules increases".

<u>Option: </u>C

<u>Explanation:</u>

The temperature relates to a gas, according to the kinetic theory of gases, influences the rate of motion of the gas particles. The higher the gas temperature, the faster the gas particles are moving; the reverse is true, too.

This is because the gas particles gain more kinetic energy as the temperature of the gas increases, and therefore move faster and collide more with each other and the container walls.The rate of a gas's molecules is proportional to the temperature, and is inversely proportional to the gas's molar mass.

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If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T

Veronika [31]

Answer:

$m_{MnO_2}=21.2gMnO_2$

Explanation:

Hello,

In this case, given the balanced reaction:

$2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O$

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

$m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-} *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2$

Best regards.

5 0

4 years ago

The volume of a gas held at constant temperature varies indirectly as the pressure of the gas. If the volume of a gas is 1200 cu

kvasek [131]

Answer:

Volume of the gas at 500 mm Hg pressure is 960 $cm^{3}$

Explanation:

Let's assume the gas behaves ideally.

According to combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

Where $P_{1}$ and $P_{2}$ are initial and final pressure of the gas respectively. $V_{1}$ and $V_{2}$ are initial and final volume of the gas respectively. $T_{1}$ and $T_{2}$ are initial and final temperature of the gas in kelvin respectively.

Here $T_{1}$ = $T_{2}$ , $V_{1}$ = 1200 $cm^{3}$ , $P_{1}$ = 400 mm Hg, $P_{2}$ = 500 mm Hg

So, $V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$

Hence $V_{2}=\frac{400\times 1200}{500}[tex]cm^{3}$ =960 $cm^{3}$ [/tex]

Hence volume of the gas at 500 mm Hg pressure is 960 $cm^{3}$

3 0

4 years ago

The ratio of nitrogen to oxygen by mass in NO is 7.0:8.0. Identify the ratio of nitrogen to oxygen by mass in NO2 and N2O7 .

Rus_ich [418]

This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.

<h3>Mass ratios:</h3>

In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:

$\frac{14}{16}=\frac{7.0}{8.0}$

Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:

$NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0} \\
\\
N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0}$

Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively

Learn more about atomic masses: brainly.com/question/5566317

3 0

3 years ago

Each energy level contains a different number of sublevels which means each

Yuki888 [10]

The answer is D because the each energy level contains a different numbers

6 0

4 years ago

15 pts The drop down items have the same options for all sections labeled choose an item

tia_tia [17]

Answer:

#8 : 21.5 L of CH₄

#9 : 36 g of H₂O

#9 : 5.4 x 10²² molecules of CO₂

Explanation:

#8 : Part 1.

Data given:

no. of moles of CH₄ = 0.960 mol

volume of CH₄ = ?

Solution

volume can be calculated by following formula

No. of moles = Volume of gas / molar volume

Rearrange the above equation

Volume of gas = No. of moles x molar volume . . . . . . (1)

Where

molar volume = 22.4 L/mol

Put values in equation 1

Volume of gas = 0.960 mol x 22.4 L/mol

Volume of gas = 21.5 L

So,

By calculation 0.960 moles have 21.5 L volume of CH₄

_______________

#9 : Part 2.

Data given:

no. of moles of H₂O = 2.0 mol

mass of H₂O = ?

Solution

volume can be calculated by following formula

No. of moles = mass in grams / molar mass

Rearrange the above equation

mass in grams = No. of moles x molar mass . . . . . . (2)

Where

molar mass of H₂O = 2 (1) + 16

molar mass of H₂O = 18 g/mol

Put values in equation 2

mass in grams = 2.0 mol x 18 g/mol

mass in grams = 36 g

So,

By calculation 2.0 moles have 36 g mass of H₂O

________________

#10 : Part 3.

Data given:

volume of CO₂ = 2 L

no. of molecules of CO₂ = ?

Solution

First we have to find out number of moles of CO₂

Following formula will be used

No. of moles = Volume of gas / molar volume

Where

molar volume = 22.4 L/mol

Put values in above equation

No. of moles = 2 L / 22.4 L/mol

No. of moles = 0.0893 mol

So,

No. of moles of CO₂ = 0.0893 mol

Now

we will calculate number of molecules by using following formula

No. of moles = no. of molecules / Avogadro's number

Rearrange the above equation

no. of molecules = No. of moles x Avogadro's number . . . . . . (3)

Where

Avogadro's number = 6.022 x 10²³

Put values in above equation 3

no. of molecules = 0.0893 mol x 6.022 x 10²³

no. of molecules = 5.4 x 10²²

So,

By calculation 2 L of CO₂ have 5.4 x 10²² molecules of CO₂

8 0

4 years ago