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Paul [167]
3 years ago
9

Is cool-aid a element ,compound or mixture?

Chemistry
2 answers:
mamaluj [8]3 years ago
8 0
Cool-aid is a mixture because it is a mixture of non-organic substances, dyes, and artificial flavors. Hoped I helped!
Cerrena [4.2K]3 years ago
6 0
Kool-aid is a mixture.
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Commercial manufacturers produce nitric acid (HNO3) by the Ostwald process. The process requires three steps:
Shkiper50 [21]

Answer:

this doesnt make sence ezxplain the subject

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What the answer question
Serga [27]

Answer:

it's a trigonal bipyramidial

Explanation:

because NH3 have 3 hydrogen atoms

4 0
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A Variable That Stays The Same In An Experiment Is A ?
hammer [34]
The variable that stays the same in an experiment is called the controlled variable

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3 years ago
Balance each skeleton reaction, use Appendix D to calculate E°cell , and state whether the reaction is spontaneous:(a) Cu⁺(aq) +
melamori03 [73]

The balanced equation reaction :

2Cu+(aq) + PbO2(s) + SO42–(aq) + 4H+  -----------> PbSO4(s) + 2 Cu2+(aq)  + 2H2O

A balanced equation is an equation for a chemical reaction in which the range of atoms for every detail in the reaction and the full charge is identical for both the reactants and the products. In other phrases, the mass and the fee are balanced in each aspect of the reaction.

A balanced equation happens while the variety of the atoms involved inside the reactants side is identical to the variety of atoms in the goods facet. in this chemical reaction, nitrogen (N2) reacts with hydrogen (H) to provide ammonia (NH3). The reactants are nitrogen and hydrogen, and the product is ammonia.

A chemical equation is the symbolic representation of a chemical reaction inside the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities.

Eo  = Eored - Eo oxd

 = 1.69  - 0.153

 = 1.54 V

Eocell is positive so the reaction is spontaneous.

Learn more about the balanced reaction  here brainly.com/question/15355912

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4 0
2 years ago
Consider the reaction of Mg3N2 with H2O to form Mg(OH)2 and NH3. If 4.33 g H2O is reacted with excess Mg3N2 and 6.26 g of Mg(OH)
Len [333]

Answer:

89.34%

Explanation:

First, write a balanced reaction.

Mg3N2 + <u>6</u>H2O --> <u>3</u>Mg (OH)2 + <u>2</u>NH3

Next determine the moles of the known substance, or limiting reagent ( H2O)

n= m/MM

n ( H2O) = 4.33/(1.008×2)+16

n(H2O)= 0.2403

Use the mole ratio to find the moles of Mg(OH)2

0.2403 ÷2

n (Mg (OH)2) = 0.1202

Next, find the theoretical mass of Mg (OH)2 that should have been produced

m= n × MM

m= 0.1202 × (24.305 + (16×2) +(1.008 ×2))

=7.007g

To find percentage yield, divide the experimental amount by the theoretical amount and multiply by 100.

6.26/ 7.007 × 100

=89.34%

7 0
3 years ago
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