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Paul [167]
3 years ago
9

Is cool-aid a element ,compound or mixture?

Chemistry
2 answers:
mamaluj [8]3 years ago
8 0
Cool-aid is a mixture because it is a mixture of non-organic substances, dyes, and artificial flavors. Hoped I helped!
Cerrena [4.2K]3 years ago
6 0
Kool-aid is a mixture.
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Scientists can tell the average temperature of the earth by studying an ice core.<br> true or false
Nata [24]
False. Because though some part of the Earth does have ice, ice is far different from land. As well as I dont think there is even such a thing as an "ice core", by means of other planets. <span />
5 0
3 years ago
Read 2 more answers
Calculate how many moles of carbon dioxide are contained in 5.57 x 10²¹ molecules of CO₂
Alex777 [14]
<h2>Answer:  0.00925 mol </h2>

Explanation:

Moles = # of molecules ÷ Avogadro's Number  

         =  (5.57 × 10²¹ molecules) ÷ (6.022 × 10²³ molecules/mol)  

         =  0.00925 mol

<h3>∴ the 5.57 x 10²¹ molecules of carbon dioxide ≡ 0.00925 mol</h3>
3 0
2 years ago
In order to complete his research project, Roger needs to make a mixture of 86 mL of a 36% acid solution from a 39% acid
Zina [86]

The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.

The mixture of the acids solutions is given by:

CV = C_{1}V_{1} + C_{2}V_{2}    (1)      

Where:

C: is the concentration if the mixture = 36%  

V: is the total volume of the mixture = 86 mL

C₁: is the concentration of acid 1 = 39%

V₁: is the volume if acid 1 =?

C₂: is the concentration of acid 2 = 17%

V₂: is the volume of acid 2

The sum of V₁ and V₂ must be equal to V, so:

V = V_{1} + V_{2}

V_{2} = V - V_{1}  (2)

By entering equation (2) into (1), we have:

CV = C_{1}V_{1} + C_{2}(V - V_{1})

36\%*86 mL = 39\%*V_{1} + 17\%(86 mL - V_{1})

Changing the percent values to decimal ones:

0.36*86 mL = 0.39*V_{1} + 0.17(86 mL - V_{1})  

Now, by solving the above equation for V₁:

V_{1} = 74.27 mL  

Therefore, the volume of the 39% acid solution is 74.27 mL.

       

To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults

I hope it helps you!  

         

7 0
2 years ago
Read 2 more answers
If you add 14.22ml of 2.97m hcl (42.2mmol) to an antacid, then neutralize the excess acid with 5.00ml of 0.1055 m naoh (0.528mmo
Vinvika [58]

Given data:

Volume of HCl = 14.22 ml

Molarity of HCl = 2.97 M

mmoles of HCl = 14.22 * 2.97 = 42.2 mmoles

Volume of NaOH = 5.00 ml

Molarity of NaOH = 0.1055 M

mmoles of NaOH = 5.00 *.1055 = 0.5275 mmoles

Since HCl and NaOH combine in a 1:1 ratio

# moles of NaOH = # moles of excess HCl that is neutralized = 0.5275 moles

Now, the total moles of HCl taken = # mmoles HCl neutralized by antacid + # mmoles of excess HCl

42.2 = mmoles HCl neutralized by antacid + 0.5275

Therefore,

mmoles of HCl neutralized by antacid = 42.2 - 0.5275 = 41.6725 mmoles = 41.7 mmoles


5 0
3 years ago
Which of the following will increase the volume of a gas?
Dmitry_Shevchenko [17]

Answer:

B. Decreasing the pressure applied to the gas molecules

Explanation:

According to Boyle's Law, the pressure of the gas is inversely proportional to the volume of the gas. So, the option B is correctly implied to it.

Other values such as Temperature, Number of molecules are inversely proportional to the volume of the gas.

Size of the gas molecules is negligible as compared to volume.

7 0
3 years ago
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