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Alika [10]
3 years ago
9

The protons and neutronsA. leave the nucleus often.B. never leave the nucleus.C. spend all their time outside the nucleus.

Chemistry
1 answer:
nika2105 [10]3 years ago
6 0
B. never leave the nucleus.
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The reation between sulfur dioxide and oxygen is a dynamic equilibrium. what happens when the pressure of the system is
ZanzabumX [31]

Answer:

In the above reaction, sulfur dioxide and oxygen react together to form sulfur trioxide. This means that an increase in pressure would move the equilibrium to the right and result in more sulfur trioxide being formed. Pressure can only affect the position of equilibrium if there is a change in the total gas volume.

5 0
3 years ago
Material
ziro4ka [17]
What are you trying to ask
5 0
3 years ago
1. Which of the following should have the highest boiling point?
amm1812

Answer:

1. CBr4

2. C5H12

3. CF4

4. C8H17NH2

Explanation:

1. The boiling point of a molecule depends on its structure. Because the boiling point of molecules of similar size, depends on the differences in functional groups of the molecule.

For example CBr4 have a higher boiling point than other compounds because they have both London dispersion forces and dipole-dipole interactions.

2. Non-polar molecules like C5H12 will have low melting and boiling points, because they are held together by the weak van der Waals forces.

7 0
3 years ago
Why is the scientific process a flexible process? Please help I need to know this for finals.
Aleks04 [339]
The scientific process has to adapt to what the experiment is.
3 0
3 years ago
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
3 years ago
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