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siniylev [52]
3 years ago
5

This equation represents cellular respiration.

Chemistry
1 answer:
andre [41]3 years ago
6 0

if you work it put you will get the 3rd one I think

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What is the main product of the fusion reactions in our sun?
RUDIKE [14]
The sun generates its energy by nuclear fusion of hydrogen nuclei into helium.
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4 years ago
Scientists can make atoms of large elements which have not been previously known. Identify an element that would have similar pr
olasank [31]

Answer:

Radon

Explanation:

One element that will have similar property as an atom with 118 protons is Radon because it will belong to the p-block and the noble gas group.

The element will follow atomic number 117 which is already in the 7th group on the periodic table.

  • Generally, on the periodic table, elements in the same group will have the same chemical property.
  • The valency of most elements determines their chemical behavior.
  • Since our mystery element is in the 8th group, noble gas group, it will mostly behave like any of the elements in the group.
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4 years ago
Explain what is meant by energy and list two units in which energy is measured
dybincka [34]

Answer:

J (joule)  W(watt)

Explanation:

If you're looking for the definition it is

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4 0
3 years ago
(4.03 Q1) What is a substance which cannot be broken down into different
sergejj [24]

Answer:

An element

Elements are substances that cannot be broken down into simpler substances either by physical or chemical method.

4 0
3 years ago
the combustion of octane is given in this reaction 2C8H18+2502-----16CO2+18H2 O, identify the limit reagent for this reaction wi
Archy [21]

Answer:

Liming reagent in the given reaction is oxygen.

Explanation:

Mass of octane = 12.85 g

Mass of oxygen = 7.46 g

Molar mass of octane = 114.23 g/mol

Molar mass of oxygen = 32

Mole=\frac{Mass\;in\;g}{Molar\;mass}

No.\;of\;moles\;of\;octane=\frac{12.85}{114.23} = 0.1125\;mol

No.\;of\;moles\;of\;oxygen=\frac{7.46}{32} = 0.2331\;mol

2C_8H_{18} + 25O_2 \rightarrow 16CO_2 +18H_2O

According to the reaction, 2 moles of octane requires 25 moles of O2

so, 0.1125 moles of octane requires 0.1125\times \frac{25}{2}  = 1.40625\;mol of oxygen.

but only 0.2331 mol of oxygen is present.

Hence, oxygen is the limiting reagent

4 0
3 years ago
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