3 years ago

Please help! Will vote brainliest!

Mathematics

1 answer:

adoni [48]3 years ago

6 0

Step-by-step explanation:

D={0,1,2,..}

E={1,4,9,16,25}

F={22,24,26,28}

expression 4 is correct

You might be interested in

suppose the divisor and the dividend of a division problem are both fractions between 0 and 1, and the divisor is greater than t

Virty [35]

Divisor and Dividend are fractions lying between 0 and 1

Also, Divisor > Dividend

⇒ A smaller number is being divided by a larger number

Whenever a smaller number is divided by a larger number, the quotient is less than 1

E.g. Let divisor be $\frac{4}{5}$ and dividend be $\frac{2}{5}$

$\frac{4}{5}$ ÷ $\frac{4}{5}$ = $\frac{1}{2}$ , which is less than 1

Hence, the answer is that the quotient will be less than 1

7 0

3 years ago

Read 2 more answers

The sum of digits in a two-digit number is 7. If the digits switch place you get a number bigger by 27. What's that number?

-Dominant- [34]

Step-by-step explanation:

the solution is found in the images above

4 0

3 years ago

Select the expressions whose value is 4. <br> (-2)² <br> |- 4| <br> - 4÷2 <br> 2(-2)

Dmitry [639]

The first and the second one.

-2*-2=4

Absolute value of -4 is 4

7 0

2 years ago

Use multiples to write two fractions equivalent to 9/10

pochemuha

18/20 and 27/30 hope this helps

8 0

3 years ago

Read 2 more answers

The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).

lesantik [10]

Answer:

(a).

$S_{n} = \frac{n}{2} (4n + 20) \\ \\S _{n - 1} = \frac{(n - 1)}{2} (4n - 4 + 20) \\ \\ S _{n - 1} = \frac{(n - 1)}{2} (4n + 16) \\ \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2} \\ \\ { \boxed{S _{n - 1} = {2 {n}^{2} + 6n - 8}}} \\$

(b).

from general equation:

$S _{n - 1} = \frac{(n - 1)}{2} (4n + 16)$

first term is 4n

common difference:

$16 = \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d = \frac{16}{n - 2}$

8 0

3 years ago