The answer goes up by 12 each time
Here are the numbers that represent each based on the box plot:
Median: 11 (located at the vertical line in the middle of the box)
Range: 19 - 7 = 12 (highest value - lowest value)
25%: 9 (at the left end of the box)
75%: 14 (at the right end of the box)
Interquartile range: 14 - 9 = 5 (the distance from the beginning to the end of the middle half of the data)
Answer:
9) C. 35 + 0.12x = 44.36
10) B
11) A. 32
Step-by-step explanation:
9)
44.36 is the TOTAL so the equations have to EQUAL it.
PER mile means it's a variable so it's 0.12x:
35 is a constant so there's no variable attached:
35 + 0.12x = 44.36
10)
B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.
11)
0.1x + 0.25(46 - x) = 6.70
0.1x + 11.5 - 0.25x = 6.7
-0.15x = 6.7 - 11.5
-0.15x = -4.8
x = 32
The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Given an equation showing profits of A Christmas vendor as
P=-0.1
+30g-1200.
We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.
To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.
665.60=-0.1
+30g-1200
0.1
-30g+1200+665.60=0
0.1
-30g+1865.60=0
Divide the above equation by 0.1.
-300g+18656=0
Solving for g we get,
g=[300±
]/2*1
g=[300±![\sqrt{90000-74624}]/2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-74624%7D%5D%2F2)
g=[300±
]/2
g=(300±124)/2
g=(300+124)/2 , g=(300-124)/2
g=424/2, g=176/2
g=212,88
Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.
Put the value of P=1500 in equation P=-0.1
+30g-1200.
-0.1
+30g-1200=1500
0.1
-30g+1500+1200=0
0.1
-30g+2700=0
Dividing equation by 0.1.
-300g+27000=0
Solving the equation for finding value of g.
g=[300±
]/2*1
=[300±![\sqrt{90000-108000}] /2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-108000%7D%5D%20%2F2)
=[300±
]/2
Because
comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.
Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Learn more about equation at brainly.com/question/2972832
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