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3 years ago

Favorite type of music, choose the correct level of measurement

Mathematics

1 answer:

otez555 [7]3 years ago

6 0

Answer:

The answer is "Nominal"

Step-by-step explanation:

Some of the data is missing which is defined in the attached file. please find it.

The standard measuring degree is nominal for the favorite type of music because the type of music it can be listening for depends on a variety of factors, like age, social or local environment, etc, and the wrong choice can be defined as follows:

It is wrong because the Ordinal does have a nominal or measuring element, however, the name system allows a ranked or a specific series of variables for all the variables to also be organized.
The ratio has the structure infections rate property, as well as the quantities ranges of the variable, provide value, that's why it is incorrect.
It is wrong because the internal has the property of ordinal level rate as well as the vector values have significance.

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Pleas help me find the answer and show the work to this question

lions [1.4K]

Answer:

$Leg\ 1 = 8$

$Leg\ 2 = 15$

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

$Hyp^2 = Adj^2 + Opp^2$

In this case:

$17^2 = x^2 + (2x- 1)^2$

Open Bracket

$17^2 = x^2 + 4x^2- 2x-2x + 1$

$17^2 = 5x^2 - 4x + 1$

$289= 5x^2 - 4x + 1$

Collect Like Terms

$5x^2 - 4x + 1 - 289 = 0$

$5x^2 - 4x - 288 = 0$

Solving using quadratic formula:

$x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

So:

$x = 8$ or $x = -7.2$

Since, x can't be negative, then:

$x = 8$

One of the leg is:

$Leg\ 1 = x$

$Leg\ 1 = 8$

$Leg\ 2 = 2x - 1$

$Leg\ 2 = 2*8 - 1$

$Leg\ 2 = 16 - 1$

$Leg\ 2 = 15$

6 0

2 years ago

The top one I need help with

brilliants [131]

Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12

5 0

3 years ago

An aquarium is in the shape of a cube. The aquarium can hold between 4096 cubic inches and 8000 cubic inches of water. What are

pantera1 [17]

Answer: The possible side lengths are either 16 inches or 20 inches

Step-by-step explanation: The aquarium is in the shape of a cube which suggests that, all dimensions (length, width and height) are equal.

If it can hold 4096 cubic inches of water, then the volume of water in it can be calculated as follows;

Volume = L x W x H

Knowing that all three dimensions are the same the formula can be re-written as;

Volume = L³

4096 = L³

Add the cube root sign to both sides of the equation

∛4096 = ∛L³

16 = L

Also if it can hold up to 8000 cubic inches of water, then the volume of water in it can be calculated as;

Volume = L³

8000 = L³

Add the cube root sign to both sides of the equation

∛8000 = ∛L³

20 = L

Therefore, if the aquarium can hold between 4096 and 8000 cubic inches of water, then the side lengths are either 16 inches or 20 inches

3 0

3 years ago

What is the correct interpretation of the point (250, 0)? The average price per ticket is $250. The minimum price per ticket is

Brut [27]

The point (250,0) of the graph represents that the average price per ticket is $250.

Given to us

x is the price the passenger paid

f(x) is the positive percent difference

<h3>What is the correct interpretation of the point (250, 0)?</h3>

We know that a coordinate is written in the form of (x, y), therefore, the point (250, 0) represents that the price of the ticket is 250, while the 0 in the coordinate represents that there is no percentage difference. Since the point (250,0) is the mid-value of the x-axis on the graph, we can say that $250 is the average price of the ticket.

Hence, the point (250,0) of the graph represents that the average price per ticket is $250.

Learn more about Graph:

brainly.com/question/14375099

5 0

2 years ago

Strain-displacement relationship) Consider a unit cube of a solid occupying the region 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1 After loa

Anastasy [175]

Answer:

please see answers are as in the explanation.

Step-by-step explanation:

As from the data of complete question,

$0\leq x\leq 1\\0\leq y\leq 1\\0\leq z\leq 1\\u= \alpha x\\v=\beta y\\w=0$

The question also has 3 parts given as

Part a: Sketch the deformed shape for α=0.03, β=-0.01 .

Solution

As w is 0 so the deflection is only in the x and y plane and thus can be sketched in xy plane.

the new points are calculated as follows

Point A(x=0,y=0)

Point A'(x+αx,y+βy)

Point A'(0+(0.03)(0),0+(-0.01)(0))

Point A'(0,0)

Point B(x=1,y=0)

Point B'(x+αx,y+βy)

Point B'(1+(0.03)(1),0+(-0.01)(0))

Point B'(1.03,0)

Point C(x=1,y=1)

Point C'(x+αx,y+βy)

Point C'(1+(0.03)(1),1+(-0.01)(1))

Point C'(1.03,0.99)

Point D(x=0,y=1)

Point D'(x+αx,y+βy)

Point D'(0+(0.03)(0),1+(-0.01)(1))

Point D'(0,0.99)

So the new points are A'(0,0), B'(1.03,0), C'(1.03,0.99) and D'(0,0.99)

The plot is attached with the solution.

Part b: Calculate the six strain components.

Solution

Normal Strain Components

$\epsilon_{xx}=\frac{\partial u}{\partial x}=\frac{\partial (\alpha x)}{\partial x}=\alpha =0.03\\\epsilon_{yy}=\frac{\partial v}{\partial y}=\frac{\partial ( \beta y)}{\partial y}=\beta =-0.01\\\epsilon_{zz}=\frac{\partial w}{\partial z}=\frac{\partial (0)}{\partial z}=0\\$

Shear Strain Components

$\gamma_{xy}=\gamma_{yx}=\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x}=0\\\gamma_{xz}=\gamma_{zx}=\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x}=0\\\gamma_{yz}=\gamma_{zy}=\frac{\partial w}{\partial y}+\frac{\partial v}{\partial z}=0$

Part c: Find the volume change

$\Delta V=(1.03 \times 0.99 \times 1)-(1 \times 1 \times 1)\\\Delta V=(1.0197)-(1)\\\Delta V=0.0197\\$

Also the change in volume is 0.0197

For the unit cube, the change in terms of strains is given as

$\Delta V={V_0}[(1+\epsilon_{xx})]\times[(1+\epsilon_{yy})]\times [(1+\epsilon_{zz})]-[1 \times 1 \times 1]\\\Delta V={V_0}[1+\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}+\epsilon_{xx}\epsilon_{zz}+\epsilon_{yy}\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}\epsilon_{zz}-1]\\\Delta V={V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\$

As the strain values are small second and higher order values are ignored so

$\Delta V\approx {V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\ \Delta V\approx [\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\$

As the initial volume of cube is unitary so this result can be proved.

5 0

2 years ago