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-4 is also a geometric mean
if we consider a(first element in series)=1 and r(common ratio)=-4 then the series would be
1,-4,16,-64,256,…..,a(-4)^(n-1 )
where n is nth term
from this -4 would be the geometric mean if we consider -4 as common ratio .
If we consider 4 as common ratio then geometric mean should be 4
so you should mention whether common ratio >0 or not (r>0 or not) .
[without ‘r’ value you can’t solve the question but in general most of the teachers will consider r>0.]
So, -4 won’t be geometric mean of 1 & 16
Answer:
Step-by-step explanation:
We are given that
Function f decreases from quadrant 2 to quadrant 1 and approaches y=0
It cut the y- axis at (0,6) and passing through the point (1,2).
Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.
It passing through the point (-1,2) and cut the y-axis at point (0,6).
Reflection across y- axis:
Rule of transformation is given by
Using the rule then we get
By using
Substitute x=-1
Substitute x=0
Therefore, is true.
5 1/2 + p = 6
subtract 5 /12 from each side
5 1/2 - 5 1/2+ p = 6 - 5 1/2
p = 6 - 5 1/2
borrow from the 6
p = 5 2/2 - 5 1/2
p = 1/2