Answer:
(x^4-8)^45 /180 +c
Step-by-step explanation:
If u=x^4-8, then du=(4x^3-0)dx or du=4x^3 dx by power and constant rule.
If du=4x^3 dx, then du/4=x^3 dx. I just divided both sides by 4.
Now we are ready to make substitutions into our integral.
Int(x^3 (x^4-8)^44 dx)
Int(((x^4-8)^44 x^3 dx)
Int(u^44 du/4)
1/4 Int(u^44 dul
1/4 × (u^45 / 45 )+c
Put back in terms of x:
1/4 × (x^4-8)^45/45 +c
We could multiply those fractions
(x^4-8)^45 /180 +c
<span>Assuming that this is referring to the same list of options that was posted before with this question, the correct response was the first one, although I forget what it was. </span>
The answer to that question is 62x ()//‘’::;;
Do 10 to the sixth power first then multiply that by 7 you use PEMDAS
Answer:
x = 27/5
Step-by-step explanation:
5x - 1 = 26
Add 1 to each side
5x - 1 = 26
5x-1+1 = 26+1
5x = 27
Divide each side by 5
5x/5 = 27/5
x = 27/5
