Answer:
5 .52
Step-by-step explanation:
do the math. aaaaaaaaaaaaaaaaaaaannnnnnnnnnnnnnnnnddddddd this is the best appppp evvvvver
Answer:
Approximate length of the diagonal fencing needed is 45.25 cm.
Step-by-step explanation:
Here, each side of the square shaped land = 32 ft
Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.
<u>In the triangle:</u>
Base side of the triangle = 32 cm
Perpendicular length of the triangle = 32 cm
Let us assume the hypotenuse of the triangle = k cm
⇒The length of the diagonal in the square = k cm
by <u>PYTHAGORAS THEOREM</u> in a right angled triangle:
![(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}](https://tex.z-dn.net/?f=%28Base%29%5E%7B2%7D%20%2B%20%20%28Perpendicular%29%5E%7B2%7D%20%20%3D%20%20%28Hypotenuse%29%5E%7B2%7D)
⇒![(32)^2 + (32)^2 =k^2\\or, k^2 = 1024 + 1024 = 2048\\\implies k = \sqrt{2048} = 45.25](https://tex.z-dn.net/?f=%2832%29%5E2%20%2B%20%2832%29%5E2%20%20%3Dk%5E2%5C%5Cor%2C%20k%5E2%20%20%3D%201024%20%2B%201024%20%3D%20%202048%5C%5C%5Cimplies%20k%20%3D%20%5Csqrt%7B2048%7D%20%20%3D%2045.25)
or, k = 45.25 cm
Hence,the approximate length of the diagonal fencing needed to fence the square land is 45.25 cm.
Answer:
8500 mm is greater
Step-by-step explanation:
800 cm= 8000 mm
8000<8500 mm
The inequality is used to solve how many hours of television Julia can still watch this week is ![x + 1.5 \leq 5](https://tex.z-dn.net/?f=x%20%2B%201.5%20%5Cleq%205)
The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours
<h3><u>Solution:</u></h3>
Given that Julia is allowed to watch no more than 5 hours of television a week
So far this week, she has watched 1.5 hours
To find: number of hours Julia can still watch this week
<em>Let "x" be the number of hours Julia can still watch television this week</em>
"no more than 5" means less than or equal to 5 ( ≤ 5 )
Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours
number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch
![x + 1.5 \leq5](https://tex.z-dn.net/?f=x%20%2B%201.5%20%5Cleq5)
Thus the above inequality is used to solve how many hours of television Julia can still watch this week.
Solving the inequality,
![x + 1.5 \leq5\\\\x \leq 5 - 1.5\\\\x \leq 3.5](https://tex.z-dn.net/?f=x%20%2B%201.5%20%5Cleq5%5C%5C%5C%5Cx%20%5Cleq%205%20-%201.5%5C%5C%5C%5Cx%20%5Cleq%203.5)
Thus Julia still can watch Television for 3.5 hours