The half-life of the radioactive substance can be determined through teh equation ln 2 = k (t 1/2) where k is equal to ln (1/(1-0.58)) / 3. Hence t 1/2 is equal to 2.40 days. To decay to 10% of the original amount, ln (1/0.90) / ( ln2) / 2.40, time is equal to 0.37 days.
Answer:
1/2d+c^2-b = 21
Step-by-st ep explanation:
= 1/2(10) + 5^2 -9
= 5 + 25 - 9
= 30 - 9
= 21
I think triangle ZYX by asa
Answer:
3.745 kg
Step-by-step explanation:
