Ask question

Ask question

All categories

2 years ago

5

Help me with this exponent problem thanks Srry for the bad quality

2 answers:

irakobra [83]2 years ago

7 0

Hi! Could you type the question out.

melamori03 [73]2 years ago

3 0

<em>l</em><em>ook</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>p</em><em>icture</em>

<em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>for</em><em> </em><em>your</em><em> </em><em>test</em><em>.</em><em>.</em><em>.</em>

You might be interested in

Help me figure this out.

sleet_krkn [62]

Let me help you,
For this question, you should know that 2 2/4 is equal to 10/4.
So we know that 10/4 is 10 times 1/4.
If Julie has 1/4-cup measuring cup, then she should use her cup 10 times to get 2 2/4 cups of raisins.
Have a good one!

5 0

2 years ago

Find the value of r 4(x-3)-r+2x=5(3x-7)-9x

vlabodo [156]

r = 4(x-3)/5(3x-7) + 11x

6 0

2 years ago

One - fifth as a percentage?

nikitadnepr [17]

Answer: 0.2

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Two collinear points on a line are given in the table below:

katrin [286]

Answer:

$(4,3)$ and $(7,2)$ do not lie on the line

Step-by-step explanation:

Given

$(0,0)\ and\ (2,1)$

Required

Determine which points that are not on the line

First, we need to determine the slope (m) of the line:

$m = \frac{y_2 - y_1}{x_2- x_1}$

Where

$(x_1,y_1) = (0,0)$

$(x_2,y_2) = (2,1)$

So;

$m = \frac{y_2 - y_1}{x_2- x_1}$

$m = \frac{1 - 0}{2-0}$

$m = \frac{1}{2}$

Next, we determine the line equation using:

$y - y_1 = m(x -x_1)$

Where

$m = \frac{1}{2}$

$(x_1,y_1) = (0,0)$

$y - y_1 = m(x -x_1)$ becomes

$y - 0 = \frac{1}{2}(x - 0)$

$y = \frac{1}{2}x$

To determine which point is on the line, we simply plug in the values of x to in the equation check.

For $(4,2)$

$x = 4$ and $y =2$

Substitute 4 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 4$

$2 = \frac{4}{2}$

$2=2$

<em>This point is on the graph</em>

<em></em>

For $(4,3)$

$x = 4$ and $y = 3$

Substitute 4 for x and 3 for y in $y = \frac{1}{2}x$

$3 = \frac{1}{2} * 4$

$3 = \frac{4}{2}$

$3 \neq 2$

<em>This point is not on the graph</em>

<em></em>

For $(7,2)$

$x = 7$ and $y = 2$

Substitute 7 for x and 2 for y in $y = \frac{1}{2}x$

$2 = \frac{1}{2} * 7$

$2 = \frac{7}{2}$

$2 \neq 3.5$

<em></em>

<em>This point is not on the graph</em>

<em></em>

<em></em> $(\frac{4}{8},\frac{2}{8})$ <em></em>

<em></em> $x = \frac{4}{8}$ and<em> </em> $y = \frac{2}{8}$ <em></em>

<em>Substitute </em> $\frac{4}{8}$ <em> for x and </em> $\frac{2}{8}$ <em> for y in </em> $y = \frac{1}{2}x$ <em></em>

<em></em> $\frac{2}{8} = \frac{1}{2} * \frac{4}{8}$ <em></em>

<em></em> $\frac{2}{8} = \frac{1 * 4}{8 * 2}$ <em></em>

<em></em> $\frac{2}{8} = \frac{4}{16}$ <em></em>

<em></em> $\frac{1}{4} = \frac{1}{4}$ <em></em>

<em></em>

<em>This point is on the graph</em>

3 0

2 years ago

If -48 equals 6(a) then a is what<br>

Oksi-84 [34.3K]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

<em>Expression:</em>

$\frac{-48}{6}=\frac{6}{6}a$

$-8 = a$

Your answer is -8.

I hope this helps!

8 0

2 years ago