The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
We have given that,
A line that has a gradient of 2 and passes through the line (1, 4).
We have to determine the equation of the line,
<h3>What is the gradient?</h3>
The gradient also known as the slope is the defined as
Gradient (m) = change in y coordinate / change in x coordinate
The equation of a line passing through a given point is given by the following equation
y – y₁ = m(x – x₁)
How to determine the equation of the line passing through point (1,4)
x coordinate (x₁) = 1
y coordinate (y₁) = 4
Gradient (m) = 2
Equation =
y – y₁ = m(x – x₁)
y – 4 = 2(x – 1)
Clear bracket
y – 4 = 2x – 2
Make y the subject by adding 4 to both sides
y – 4 + 4 = 2x – 2 + 4
y = 2x + 2
The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
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The tangents are equal length, so
.. 8x = x^2
We presume their length is not zero, so we can divide by x to get
.. 8 = 2x
.. 4 = x
Then the length of each tangent is 8*4 = 32 units.
(2.0×10^-4)×(3.1×10^-20)
=(2.0×3.1)×(10^4×10^-20)
=6.2×10^(-4+(-20))
=6.2×10^-24. Hope it help!
Answer:
D. 270 cm2
Step-by-step explanation:
2*(15*5 + 15*3 + 5*3) = 270 cm2
The last one is the correct answer
