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2 years ago

Viviana jumps rope 52 times. Josiah jumps

Mathematics

1 answer:

sveticcg [70]2 years ago

8 0

Answer:

Viviana and Josiah

Step-by-step explanation:

52+7 =59

Hope this helps!!

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2x - 3y = 8 // <br><br> Find y

konstantin123 [22]

Answer:

$y = -\frac{2}{3} x - \frac{8}{3}$

Step-by-step explanation:

$2x - 3y = 8\\$

Isolate y

$-3y = 8-2x\\-3y = -2x+8$

Divide both sides of the equation by -3

$\frac{-3y}{-3} = \frac{2x}{-3} +\frac{8}{-3} \\\\y = -\frac{2}{3} x - \frac{8}{3}$

7 0

3 years ago

Ships A and B are 1,425 feet apart and detect a submarine below them. The angle of depression from ship A to the submarine is 59

andreyandreev [35.5K]

Answer: The distance from ship B to the submarine is 1270.68 feet and the distance from ship A to the submarine is 1084.18 feet.

Step-by-step explanation:

Since we have given that

Distance between Ships A and B = 1425 feet

Angle of depression from ship A to the submarine =59°

Angle of depression from ship B to the submarine = 47°

As shown in the figure below:

Remaining angle will be

$180\textdegree-(47\textdegree+59\textdegree)\\\\=180\textdegree-106\textdegree\\\\=74\textdegree$

So, we will use "Sine formula ":

$\frac{\sin 74\textdegree}{1425}=\frac{\sin 59\textdegree}{B}\\\\B=\frac{1425\times \sin 59\textdegree}{\sin 74\textdegree}\\\\B=1270.68\ feet$

Similarly,

$\frac{\sin 74\textdegree}{1425}=\frac{\sin 47\textdegree}{A}\\\\A=\frac{1425\times \sin 47\textdegree}{\sin 74\textdegree}\\\\A=1084.18\ feet$

Hence, the distance from ship B to the submarine is 1270.68 feet and the distance from ship A to the submarine is 1084.18 feet.

4 0

3 years ago

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Identify the underlined place in 83.5851. Then round the number to that place. The 8 to the right is underlined.

Marina86 [1]

We have to round the number 83.5851 to the nearest hundredth.
If the next smallest place is greater than or equal to 5 we increase the value of the digit we are rounding to by one.
83.5851 ≈ 83.59
Answer: 83.59

8 0

2 years ago

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Find the equation that models the path of a satellite if its path is a hyperbola, a=55,000 km and c=81,000 km. Assume the center

Yuki888 [10]

Given:

Hyperbola

a=55,000 km and c=81,000 km

hyperbola is the origin and the transverse axis is horizontal

Required:

Equation of the path of a satellite

Solution:

Formula for hyperbola, (x-h)2/a2 – (x-k)2/b2 = 1

At origin, (h, k) = (0, 0)

(x-0)2/(55000)2 – (x-0)2/(81000)2 = 1

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2 years ago

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May I also have help with this question

KATRIN_1 [288]

The independent variable (the one they want) is the # of hours worked, since that determines the price.

All the other answers contain information not included in the problem

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3 years ago

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