Answer:
the first one
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors
"
Find all the squared values that lies between 360 and 630
360< 19², 20², 21², 22², 23², 24², 25² < 630
19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.
Don’t get it what r the options
7. Alternate interior
8. Congruent
9. Work:
6x - 16 = 2x + 40
4x = 56
x = 14
The answer is the 3rd one: 7n-2p