<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
5.3 repeating is the answer
Answer: Look you have a website called symbolab and another called desmos for this stuff.
Step-by-step explanation:
Answer:
23%
Step-by-step explanation:
Answer:
lowest score a college graduate must earn to qualify for a responsible position is 578
correct option is D. 578
Step-by-step explanation:
given data
mean = 500
standard deviation = 50
distribution = 6 %
to find out
What is the lowest score a college graduate must earn to qualify for a responsible position
solution
we know that here Probability P that is express as
P ( Z > x ) = 100% - 6% .....................1
so with the help of normal table
here value of Z is = 1.55 from cumulative probability 0.94
so by z score formula here x will be
x = z × standard deviation + mean ................2
so put here value
x = 1.55 × 50 + 500
x = 577.7387 ~ 578
so lowest score a college graduate must earn to qualify for a responsible position is 578