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3 years ago

How do you get the answer to 18,000 seconds = hrs?

2 answers:

5 0

First you'd convert the seconds into minutes by dividing.

18,000 / 60 (60 secs in a min) = 300 minutes

Then, similarly, you would convert the minutes into hours.

300 / 60 (60 mins in an hr) = 5 hours

The answer is 5 hours.

Nadya [2.5K]3 years ago

5 0

You would divide 18,000 seconds by 60 seconds (which is equivalent to a minute)
the you would take the number you just got and divide that number by 60 minutes (which is equivalent to an hour)
that should give you the correct answer

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Multiply the following complex numbers:<br> (9-21)(7 +61)

Andrew [12]

Answer:

-816

Step-by-step explanation:

-12*68= -816 this is probably wrong but this is what i got

3 0

3 years ago

Read 2 more answers

A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average wo

klemol [59]

Answer: A. $4.3\times10^7$

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately $6.0 \times 10^2$ megabytes of information.

1 megabyte = $10^6$ bytes

Then, The storage capacity of CD-ROM disk will be :

$10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8$

If an average word requires 14 bytes of storage, then the number of words can be stored :-

$\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7$

Hence, number of words can be stored = $4.3\times10^7$

4 0

3 years ago

Two cars leave from the same point (A) and travel along a straight road, which are at angle of 78° to each other. If their speed

densk [106]

T=(60cos78, 60sin78)

T=(12.47, 58.69)

C=45

d=√((45-12.47)^2+58.69^2)

d≈67.1km

7 0

3 years ago

A metric unit of length that is equal to one thousandth of a meter is.......

12345 [234]

The metric unit of length that is equal to one thousandth of a meter is a millimeter. 1 meter = 1000 millimeter

hope this helps

3 0

3 years ago

Read 2 more answers

A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?

kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

$f(x)=\frac{1}{2^{2x}}$ (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

$\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]$ (2)

To solve this derivative you use the following derivative formula:

$\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}$

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

$\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)$

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

$-2(ln2)2^{-2x}=-1$

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

$-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235$

With this value you calculate f(a):

$f(a)=\frac{1}{2^{2(0.235)}}=0.721$

Next, you use the general equation of line:

$y-y_o=m(x-x_o)$

for xo = a = 0.235 and yo = f(a) = 0.721:

$y-0.721=(-1)(x-0.235)\\\\y=-x+0.956$

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

$0=-x+0.956\\\\x=0.956$

hence, the x-intercept of the tangent line is 0.956

5 0

3 years ago