Question

The average temperature in Long Beach California is 80 degrees Fahrenheit with a standard deviation of 3 degrees. What percentage of temperatures fall between 80 and 89 degrees?

Answer 1

Answer:

0.4987

Step-by-step explanation:

What we must do is calculate the z value for each value and thus find what percentage each represents and the subtraction would be the percentage between those two values.

We have that z is equal to:

z = (x - m) / (sd)

x is the value to evaluate, m the mean, sd the standard deviation

So for 80 we have:

z = (80 - 80) / (3)

z = 0

and this value represents 0.5

for 89 we have:

z = (89 - 80) / (3)

z = 3

and this value represents 0.9987

we subtract:

0.9987 - 0.5 = 0.4987

Which means that it represents 49.87%