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Zarrin [17]
3 years ago
13

What are the easy ways to complete problems like these?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

You can think of this whole process as "surgically removing" the repeating part from the decimal to get it into fraction form. I'll break down the steps:

x=0.\overline{12}

We set some variable x equal to our repeating decimal.

100x=12.\overline{12}

We want to move the decimal point <em>just enough </em>to the right so that we can make the "chop" we're going to perform in the next step. Since the decimal starts repeating every two digits, we want to scoot the decimal point two places over, which we can do by multiplying it by 100. We do the same to the x to keep both sides equal.

100x-x=12.\overline{12}-0.\overline{12}

This is the "chop." We're subtracting the original value of x from both sides to get rid of the repeating part of 12.\overline{12}. On the left side, this leaves us with

99x=12

We can then divide either side of the equation by 99 to find that

x=\frac{12}{99}=\frac{4}{33}

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PLEASE HELP. WILL GIVE BRAINLIEST FOR CORRECT ANSWER
lozanna [386]
Are of shaded region = area of circle - area of segment
= \pi {r}^{2}  - ((\alpha  \div 360) \times \pi \times  {r}^{2} )
= \pi {r}^{2} (1 -  \alpha  \div 360)
r = 8.35 \\  \alpha  = 100
= 158.1666....
rounding \: up
area \: of \: shaded \: region \:  = 158.2 \: \: square ft
6 0
2 years ago
Determine the equation of the line that is perpendicular to the lines r(t)=(-2+3t,2t,3t)
Mnenie [13.5K]
<span>Vector Equation
(Line)</span>(x,y) = (x,y) + t(a,b);tERParametric Formx = x + t(a), y = y + t(b); tERr = (-4,-2) + t((-3,5);tERFind the vector equation of the line passing through A(-4,-2) & parallel to m = (-3,5)<span>Point: (2,5)
Create a direction vector: AB = (-1 - 2, 4 - 5) 
= (-3,-1) or (3,1)when -1 (or any scalar multiple) is divided out.
r = (2,5) + t(-3,-1);tER</span>Find the vector equation of the line passing through A(2,5) & B(-1,4)<span>x = 4 - 3t
y = -2 + 5t
;tER</span>Write the parametric equations of the line passing through the line passing through the point A(4,-2) & with a direction vector of m =(-3,5)<span>Create Vector Equation first:
AB = (2,8)
Point: (4,-3)
r = (4,-3) + (2,8); tER
x = 4 + 2t 
y = -3 + 8t
;tER</span>Write the parametric equations of the line through A(4,-3) & B(6,5)<span>Make parametric equations: 
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in -3
-3 = 5 + 4t 
(-8 - 5)/4 = t
-2 = t
For y sub in -8 
-8 = -2 + 3t
(-8 + 2)/3 = t
-2 = t
Parameter 't' is consistent so pt(-3,-8) is on the line.</span>Given the equation r = (5,-2) + t(4,3);tER, is (-3,-8) on the line?<span>Make parametric equations: 
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in 1
-1 = 5 + 4t 
(-1 - 5)/4 = t
-1 = t
For y sub in -7 
-7 = -2 + 3t
(-7 + 2)/3 = t
-5/3 = t
Parameter 't' is inconsistent so pt(1,-7) is not on the line.</span>Given the equation r = (5,-2) + t(4,3);tER, is (1,-7) on the line?<span>Use parametric equations when generating points: 
x = 5 + 4t
y = -2 + 3t ;tER
X-int:
sub in y = 0
0 = -2 + 3t
solve for t
2/3 = t (this is the parameter that will generate the x-int) 
Sub t = 2/3 into x = 5 + 4t 
x = 5 + 4(2/3)
x = 5 + (8/3)
x = 15/3 + (8/3) 
x = 23/3
The x-int is (23/3, 0)</span>What is the x-int of the line r = (5,-2) + t(4,3); tER?Note: if they define the same line: 1) Are their direction vectors scalar multiples? 2) Check the point of one equation in the other equation (LS = RS if point is subbed in)What are the two requirements for 2 lines to define the same line?
3 0
3 years ago
Solve for x. <br><br> x + 8 = -15
anygoal [31]
1. Subtract 8 from both sides
2. Simplify to get x= -23

5 0
2 years ago
Express 24 out of 80 as a percent
olga2289 [7]

Answer:

30%

Step-by-step explanation:

24/80 = 0.3

move the decimal over 2 times and you'll get your answer

6 0
3 years ago
Can someone please help me with math.
notsponge [240]

Answer:

your answer is line plot D.

Step-by-step explanation:

7 0
2 years ago
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