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Zarrin [17]
3 years ago
13

What are the easy ways to complete problems like these?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

You can think of this whole process as "surgically removing" the repeating part from the decimal to get it into fraction form. I'll break down the steps:

x=0.\overline{12}

We set some variable x equal to our repeating decimal.

100x=12.\overline{12}

We want to move the decimal point <em>just enough </em>to the right so that we can make the "chop" we're going to perform in the next step. Since the decimal starts repeating every two digits, we want to scoot the decimal point two places over, which we can do by multiplying it by 100. We do the same to the x to keep both sides equal.

100x-x=12.\overline{12}-0.\overline{12}

This is the "chop." We're subtracting the original value of x from both sides to get rid of the repeating part of 12.\overline{12}. On the left side, this leaves us with

99x=12

We can then divide either side of the equation by 99 to find that

x=\frac{12}{99}=\frac{4}{33}

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Answer:

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3 0
3 years ago
Read 2 more answers
If y=2x^2-5x-3 find the value of y if x= -1​
Gelneren [198K]

Answer:

y = 4

Step-by-step explanation:

First we want to raise -1 to the power of 2

y = 2 * 1 - 5 * -1 - 3

Multiply

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Multiply

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y = 7 - 3

y = 4

8 0
3 years ago
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