"In Grade 2 and early in Grade 3, students learned to use bar models to solve two-step problems involving addition and subtraction. This is extended in this chapter to include multiplication and division.
Both multiplication and division are based on the concept of equal groups, or the part-part-whole concept, where each equal group is one part of the whole. In Grade 2, students showed this with one long bar (the whole) divided up into equal-sized parts, or units. This unitary bar model represents situations such as basket of apples being grouped equally into bags. " <span>https://www.sophia.org/tutorials/math-in-focus-chapter-9-bar-modeling-with-multipli</span>
Answer:
(i) the other two sides are 6 and 6
(ii) the other two sides are 
Step-by-step explanation:
(i) Sine: sin(θ) = Opposite ÷ Hypotenuse
Cosine: cos(θ) = Adjacent ÷ Hypotenuse
Tangent: tan(θ) = Opposite ÷ Adjacent
Here adjacent side = 6
opposite side = d
angle = 45°
other angles are 90° and 45°
tan (45) = Opposite ÷ Adjacent
1 = d ÷ 6
∴ d = 6 × 1 = 6
so opposite side = 6
Hypotenuse ² = opposite side ² + adjacent side²
= 6² + 6²
= 36 + 36
= 72
hypotenuse = 
= 6
the other two sides are 6 and 6
(ii) here adjacent side = 4√3
angle = 30°
other angles are 90° and 60°
opposite side = d
tan ( 30) = opposite ÷ adjacent
= d ÷ 4√3
= d × (
)
3 d = 4
therefore d = 
therefore opposite side = 
Hypotenuse ² = opposite side ² + adjacent side²
=(
)² +(
)²
= 
therefore hypotenuse = 
=
the other two sides are 
Step-by-step explanation:
1 septillion = 10^6 nonillion
the taking time = 5× 10^-6 / 257.21
= 500× 10^-8 /257.21
= 1.94 × 10^-8 seconds
Answer:
6084
.
Step-by-step explanation:
Please find the attachment.
We have been given that the home-office of Tri-star industries is made up of three square buildings, one for each department, with a triangular atrium in the middle. The area of the Plumbing building is 5,184
and the area of the A/C building is 900
.
We know that area of square is square of its side length. Since all building are squares, so to find the area of electrical building, we will use Pythagoras theorem.

We can see from our attachment that side length of electrical building is hypotenuse (c) of the right triangle.
Upon substituting our given information in Pythagoras theorem, we will get:


Therefore, the area of electrical building is 6084 square feet.