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vredina [299]
3 years ago
6

You work at a craft store that sells paint kits. The kits have 4 thin paintbrushes for every 6 thick brushes. What is

Mathematics
2 answers:
liq [111]3 years ago
6 0

Answer:2:3

Step-by-step explanation:

if you were to simplify the ratio just like you would a fraction you would get 2:3

navik [9.2K]3 years ago
3 0

Answer:

b. 3:2

Step-by-step explanation:

thick paintbrushes : thin paintbrushes

6 : 4 (both can be divide by 2,so we simplifiy by dividing both with 2)

3 : 2

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PLEASE HELP!! I’LL GIVE BRAINLY
LiRa [457]

Being that the triangle has a center of dilation at (0,0) you must contract the points towards (0,0). The scale factor is 1/3 so you must divide the difference in location of the points on the X and Y axis by a scale of 1/3.

1/3 of 9 = 3 , y = 3

1/3 of -6 = -2 , x = -2

by changing these points a new triangle will be formed

5 0
3 years ago
Cube X has a volume of x, Cube Y has a volume of 8x. If Cube Y has an edge length of y, what is the edge length of Cube X?
ziro4ka [17]
Hello,

Cube X: volume=x
Cube Y: volume=8x
Y has a volume 2^3 times of the X cube
So,
the side of the Y cube is twice the volume of the X cube.

The side of the X cube is half of the cube Y

Side of X cube=y/2

6 0
3 years ago
What are 23 times 76
aksik [14]
23 x 76 is 1748
I hope this helps :)
3 0
2 years ago
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Ivahew [28]
Wow that looks so cool!, is that toothless?
5 0
3 years ago
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Element X decays radioactively with a half life of 13 minutes. If there are 110 grams of Element X, how long, to the nearest ten
Vaselesa [24]

Answer : The time taken by the element to decay to 2 grams is, 75.2 minutes

Step-by-step explanation:

Half-life = 13 min

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{13\text{ min}}

k=0.0533\text{ min}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.0533\text{ min}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant  = 110 g

a - x = amount left after decay process =  2 g

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0533}\log\frac{110}{2}

t=75.2\text{ min}

Therefore, the time taken by the element to decay to 2 grams is, 75.2 minutes

7 0
3 years ago
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