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Sunny_sXe [5.5K]
3 years ago
10

Each base of a triangular prism is a right triangle with side lengths 3 inches, 4 inches, and 5 inches. The height of the prism

is 7 inches. What is the surface area of the prism?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0
Well, each base has 3*4/2=6 square inches. The lateral faces have 3*7, 4*7 and 5*7 as areas, totalling 12*7=84 square inches on the sides. The bases which total 12 sq. in. are added to the sides to get a total surface area of 96 square inches.
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Find f(6) if f(x) = x2 ÷ 3 + x. <br><br> 1.) 4 <br> 2.) 10 <br> 3.) 18
rodikova [14]
Plug 6 for x.

f(6) = 6^2 / 3 + 6
f(6) = 36 / 3 + 6
f(6) = 12 + 6
f(6) = 18
5 0
3 years ago
A local boys club sold 136 bags of mulch and made a total of $521. It sold two types of mulch: hardwood for $4.00 a bag and pine
Anni [7]

Answer: 14.32

Step-by-step explanation:

4 0
3 years ago
Measurements of the sodium content in samples of two brands of chocolate bar yield the following results (in grams):
Tpy6a [65]

Answer:

98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .

Step-by-step explanation:

We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;

Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95

Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60

Also, \mu_X represent the population mean for Brand B and let \mu_Y represent the population mean for Brand A.

Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;

        P.Q. = \frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where, Xbar = Sample mean for Brand B data = 36.9

            Ybar = Sample mean for Brand A data = 32.9

              n_1  = Sample size for Brand B data = 13

              n_2 = Sample size for Brand A data = 9

              s_p = \sqrt{\frac{(n_1-1)s_X^{2}+(n_2-1)s_Y^{2}  }{n_1+n_2-2} } = \sqrt{\frac{(13-1)*10.4+(9-1)*7.1 }{13+9-2} } = 3.013

Here, s^{2}_X and s^{2} _Y are sample variance of Brand B and Brand A data respectively.

So, 98% confidence interval for the difference μX−μY is given by;

P(-2.528 < t_2_0 < 2.528) = 0.98

P(-2.528 < \frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  } } < 2.528) = 0.98

P(-2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} < (Xbar -Ybar) -(\mu_X-\mu_Y) < 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ) = 0.98

P( (Xbar - Ybar) - 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} < (\mu_X-\mu_Y) < (Xbar - Ybar) + 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ) = 0.98

98% Confidence interval for μX−μY =

[ (Xbar - Ybar) - 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} , (Xbar - Ybar) + 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ]

[ (36.9 - 32.9)-2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9} , (36.9 - 32.9)+2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9} ]

[ 0.697 , 7.303 ]

Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .

                     

4 0
3 years ago
I have 6 surfaces 2 of my surfaces are smaller then the others I can stand up tall what shape am I
Arada [10]
This shape would be a rectangular prism, with 4 rectangular sides, and 2 square or smaller rectangular sides.

An example of a rectangular prism would be a brick. It has 4 sides that are perfectly alike, then two other sides that are like each other.
5 0
3 years ago
Read 2 more answers
Amelia and Jayden work at a furniture store. Amelia is paid $185 per week plus 9.5% of her total sales in dollars, xx, which can
almond37 [142]

Answer:

The weekly sales must be $12,600

Step-by-step explanation:

if their pay is the same, the equations have to be equal

amelia = jayden

185 +.095x = 311 +.085x

subtract  .085x from each side

185 +.095x-.085x = 311 +.085x-.085x

185+.01x = 311

subtract 185 from each side

185-185+.01x = 311-185

.01x = 126

divide by .01

.01x/.01 = 126/.01

x = 12600

7 0
3 years ago
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