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aksik [14]
3 years ago
12

What value of x in the solution set of 2(3x – 1) ≥ 4x – 6?

Mathematics
2 answers:
Brrunno [24]3 years ago
5 0
First, you must distribute 2(3x-1).
To do that, you will multiply 2•3x, and 2•-1 because you are taking the number outside of the parentheses and multiplying (distributing) it to all the numbers inside

After distributing, the left side of your inequality will be 6x-2

Now you have
6x - 2 \geqslant 4x - 6

To find the value of x, you must subtract an x value from both sides of the equation, as well as a constant from each side.

so you have
6x - 2 \geqslant 4x - 6 \\ - 6x \geqslant + 6
And that will make the equation
- 4 \geqslant - 2x
Now, divide the variable side, ***BUT, because you are dividing by a negative number in an inequality, the inequality will switch sides.

Then, the value of x is greater than or equal to 2
Natali5045456 [20]3 years ago
4 0

Answer:

<h2><em>-1</em></h2>

Step-by-step explanation:

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Find the area of a circle with a circumference of 6.28 unitesz
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Answer:

3.14 square units

Step-by-step explanation:

Circumference of a circle = 2πr

2πr = 6.28

r = 6.28/2π

r = 3.142/π

Area of a circle = πr^2

slot in the value of r

Area of the circle = π( 3.142/π)^2

               "              = π(9.87/ π^2)

                "             = 9.87/π

π = 3.14

Area of a circle = 9.867/ (3.14)

              "            = 3.14 square units

                     

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3 years ago
Which expression is equivalent to the square root of 2^5/18
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Temka [501]
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55% can be re-written as 55/100 OR 0.55 since percentages are always out of 100.

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4 0
3 years ago
"3. When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can sim
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Answer:

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

Step-by-step explanation:

To understand better how we arrived at the aforementioned algorithm, we take it step by step

a, Construct a min-heap of the minimum elements from each of "k" lists.

The creation of this min-heap will cost O (k) time.

b) Next we run delete Minimum and move the minimum element to the output array.

Each extraction takes O (log k) time.

c) Then insert into the heap the next element from the list from which the element was extracted.

Now, we note that  since we extract n elements in total, the running time is

O (n log k+ k) = O (n log k).

So we can conclude that :

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

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