What value of x in the solution set of 2(3x – 1) ≥ 4x – 6?

2 answers:

5 0

First, you must distribute 2(3x-1).
To do that, you will multiply 2•3x, and 2•-1 because you are taking the number outside of the parentheses and multiplying (distributing) it to all the numbers inside

After distributing, the left side of your inequality will be 6x-2

Now you have
$6x - 2 \geqslant 4x - 6$

To find the value of x, you must subtract an x value from both sides of the equation, as well as a constant from each side.

so you have
$6x - 2 \geqslant 4x - 6 \\ - 6x \geqslant + 6$
And that will make the equation
$- 4 \geqslant - 2x$
Now, divide the variable side, ***BUT, because you are dividing by a negative number in an inequality, the inequality will switch sides.

Then, the value of x is greater than or equal to 2

Natali5045456 [20]2 years ago

4 0

Answer:

Step-by-step explanation:

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