Question

You can use the equation d = 16t^2 (note: t is raised to the second power or squared) to determine the time t in seconds that it takes a dropped object to fall a distance of d feet. How long (in seconds) does a fall of 224 feet take? Round your answer to the nearest tenth. *

Answer 1

Answer:

The time the object takes to fall on the ground from 224 feet is 3.74 s.

Step-by-step explanation:

In this case we have a known quantity, the distance of the fall that is 224 feet and a equation that represents the motion of this fall that is d = 16t^2. We wish to find the time it'll take this object to fall, so we can solve this equation for t. It goes as follows:

d = 16t^2

d/16 = t^2

t^2 = d/16

t = \sqrt(d/16)

t = [\sqrt(d)]/4 = [\sqrt(224)]/4 = 14.97/4 = 3.74 s

where \sqrt is the square root of the number.

Answer 2

Answer:

3.7 seconds

Step-by-step explanation:

We were provided with the equation d=16t² so as to determine the time t in seconds it takes for an object dropped to fall a distance of d-feet.

The question says how long(in seconds does)it take for a fall of 224 feet.

16t²=d

D= 224(substitute in the equation)

16t²= 224

t²= 224/16

t=√14

t= 3.7 seconds