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Vesna [10]
3 years ago
6

A women from England sneezed 978 days in a row about how many weeks did she sneeze in a row

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0

Answer:

About 140 weeks in a row

Step-by-step explanation:

N76 [4]3 years ago
8 0

Answer:

A women from England sneezes 140 weeks in a row.

dunananana

sIsTeR sHoOk

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The circumfrance of the moon is about 6,790 miles, find the diameter of the moon to the nearest mile.
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B is the answer to this question

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What is the solution set of the equation 3x2 = 48 ?​
nalin [4]

Answer:

Step-by-step explanation:

6=48

6 0
3 years ago
a town's population is currently 5,500.if the population doubles every 91 years, what will the population be 182 years from now​
Blizzard [7]

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I think the answer is 22,000

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Hello:) anyone able to explain how to solve the equestrian for part (d) ? Thank youu
Anna007 [38]

Answer:

see explanation

Step-by-step explanation:

Given

4a^{4} - 5a² + 1 = 0

Use the substitution u = a², then equation is

4u²  - 5u + 1 = 0

Consider the product of the coefficient of the u² term and the constant term

product = 4 × 1 = 4 and sum = - 5

The factors are - 4 and - 1

Use these factors to split the u- term

4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )

4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term

(u - 1)(4u - 1) = 0

Equate each factor to zero and solve for u

u - 1 = 0 ⇒ u = 1

4u - 1 = 0 ⇒ 4u = 1 ⇒ u = \frac{1}{4}

Convert u back into terms of a, that is

a² = 1 ⇒ a = ± 1

a² = \frac{1}{4} ⇒ a = ± \frac{1}{2}

Solutions are a = ± 1 , a = ± \frac{1}{2}

7 0
3 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
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