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harina [27]
3 years ago
6

3+-√(-3)^2 - 4(5)(-1)

Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Easy way to do this is step by step.  Your quadratic, from your entry, must be

5x^2-3x-1.

Step by step looks like this, one thing at a time:

x=\frac{3+\sqrt{(-3)^2-4(5)(-1)} }{2(5)} becomes

x=\frac{3+\sqrt{9-(-20)} }{10} becomes

x=\frac{3+\sqrt{9+20} }{10}

and this of course is

x=\frac{3+\sqrt{29} }{10}

Do the same with the subtraction sign to get the other solution.

If you're unsure of how to enter it into your calculator, do it step by step so you don't mess up the sign.  If you enter it incorrectly, you could end up with an imaginary number when it should be real, or a real one that should be imaginary.

Just my advice as a high school math teacher.

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I don’t get this one
fomenos
Hi!

Two negatives make a positive, so this can be rewritten as
-7+2.5

The answer is D. -7+2.5

Hope this helps! :)
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Answer:

the new point would be (1, 10).

Step-by-step explanation:

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If you have a line that goes through (-1, 7) and (8, -2), what would the equation of the line be in point-slope form?
Eddi Din [679]

Answer:

y-9 = -1/12(x-8)

Step-by-step explanation:

To write an equation of a line perpendicular to the graph of y = 12x-3 and passing through the point, we will follow the following steps.

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Step 1: We need to calculate the slope of the known line first,

Given y = 12x-3

from the equation, m = 12 on comparison.

Step 2: get the slope of the unknown line. since the line given is perpendicular to the line y = 12x - 3, the product of their slope will be -1 i.e Mm = -1

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