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Aloiza [94]
3 years ago
10

In triangle ABC, AD is a median. FE is a straight line parallel to BC cutting the remaining sides AB at F and AC at E and cuttin

g the median at X.
If ED bisects angle ADC:


Triangle AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD.


Using above information prove that angle FDE=90
Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

Step-by-step explanation:

since AD is a median it implies that triangle ABC is bisected to two equal right angled triangle which are ADB and ADC.

FE is parrallel to BC and cuts AB at F and AC at E shows that there are two similar triangles formed which are AFE and ABC.

Recall that ADC is a right angled triangle, ED bisects a right angled triangle the the ADE = 45^{o}.

Now, Let FD bisect angle ADB,

  then ADF = 45^{o} too.

Since AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD, then EDX is similar to FDX

FDE = ADF + ADE = 90^{o}

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Answer:

7,470

Step-by-step explanation:

<u>Step 1: Convert all into inches</u>

1 feet = 12 inches

2 feet = x inches

<em>Cross multiply</em>

x = 24 inches

1 yard = 36 inches

13 yard = x inches

<em>Cross multiply</em>

x = 468 inches

<u>Step 2: Add all inches together</u>

24 + 468 + 6 = 498 inches

<u>Step 3: Multiply by 15</u>

498 x 15 = 7,470

Therefore, the answer is 7,470.

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(−4, −8), because the point satisfies both equations

Step-by-step explanation:

Line A  

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If we equate those 2 equations

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2x = -8

x = -4

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The value of 5 in 3.5 times the value of the 5 in 15 is the sentence that compares correctly with the values.

<h3>What is arithmetic?</h3>

Mathematical arithmetic is the study of the properties of the standard operations on numbers, such as addition, subtraction, multiplication, division, exponentiation, and root extraction. One of the branches of mathematics, 1a, deals with the application of addition, subtraction, multiplication, and division to nonnegative real numbers, sometimes including transfinite cardinals.

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Here, 5 in 15.2 is 1/10 times to 3.5.

The 5 in 3.5 is therefore \frac{1}{10} times the 5 in 15.2, and likewise.

The value of 5 in 3.5 times the value of the 5 in 15 is the sentence that compares correctly with the values.

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