Alex spent the summer helping out at his family

Mathematics

1 answer:

Setler79 [48]3 years ago

6 0

Hey what school do you go too

The first one is yes he'll have enough

the second one is yes because they add up to you add 28 to get up to his next week

You might be interested in

A developer wants to develop a 25-acre subdivision. He figures that the streets and common area will take up about 35% of this o

Lorico [155]

The amount avaliable for division into lots is
25 ac - 0.35*25 ac = 0.65*25 ac = 16.25 ac
There are 43,560 ft² in an acre, so the number of possible lots is
(16.25 ac)*(43,560 ft²/ac)/(25,000 ft²/lot) = 28.314 lots

The developer has enough area for 28 lots.

4 0

3 years ago

Simplify the expression 13+(x+8)

Fudgin [204]

Answer:x+21

Step-by-step explanation:

7 0

3 years ago

A veterinarian collects data on the number of times race horses are raced during their careers. The veterinarian finds that the

SpyIntel [72]

Answer:

c. (12.12, 18.48)

Step-by-step explanation:

Hello!

The study variable is X: number of times a racehorse is raced during its career.

The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.

To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:

X[bar] ± $t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{20} }$

$t_{n-1;1-\alpha /2} = t_{19;0.975}= 2.093$

[15.3 ± 2.093 * $\frac{6.8}{\sqrt{20} }$ ]

[12.12; 18.48]

Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].

I hope it helps!

8 0

4 years ago

Using Ratios to Solve Problems - Item 1457 Question 4 of 7 Evan's family drove to a theme park for vacation. They drove the same

azamat

Answer:

150 miles

distance travelled on the third day = 150 miles

Step-by-step explanation:

Note: it was given that they drove the same speed throughout the trip. That means their speed is constant for all days;

For the first day

distance = 300 miles