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icang [17]
3 years ago
8

HELP ME PLEASE IM STUCK QUICK

Mathematics
2 answers:
kari74 [83]3 years ago
7 0

Answer:

TRUE

Step-by-step explanation:

15>2

jek_recluse [69]3 years ago
5 0

Answer:

The answer is true

Step-by-step explanation:

The left side  15  is greater than the right side  2 , which means that the given statement is always true.  True

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George has opened a new store and he is monitoring its success closely. He has found that this store's revenue each month can be
makvit [3.9K]

Answer:

The new store will have a profit of $5400 after its fifth month.

(R-C)(x) = (x²+5x+14)-(x²-4x+5) = x²-x²+5x--4x+14-5 = 5x+4x+14-5=9x+9

(Use 5 for x)

(R-C)(5) = 9(5) + 9 = 45+9 = 54

6 0
2 years ago
A circle has a circumference of 361\pi361π361, pi. What is the diameter of the circle?
denpristay [2]
Remember, C=\pi d, where C is circumference and tex]d[/tex] is the diameter. They are related by a constant \pi (pi).

We can solve the above equation for d and then substitute our known values.
C=\pi d

d= \dfrac{C}{ \pi } =  \dfrac{361  \pi }{ \pi } = 361 \ units
7 0
3 years ago
ILL MARK BRAINLIEST ---Nicole is factoring 0.49t^18-25 by using the rule a^2- b^2 = (a+b)(a-b) which expression will she use for
lubasha [3.4K]
0.7t^9 I just took the test and that is the right ansswer
8 0
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Please answer >.<
gladu [14]
Answer: the total amount of money that the investor would have after 6 years will be $ 536.04 :)
5 0
2 years ago
Solve y" + y = tet, y(0) = 0, y'(0) = 0 using Laplace transforms.
irina1246 [14]

Answer:

The solution of the diferential equation is:

y(t)=\frac{1}{2}cos(t)- \frac{1}{2}e^{t}+\frac{t}{2} e^{t}

Step-by-step explanation:

Given y" + y = te^{t}; y(0) = 0 ; y'(0) = 0

We need to use the Laplace transform to solve it.

ℒ[y" + y]=ℒ[te^{t}]

ℒ[y"]+ℒ[y]=ℒ[te^{t}]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]+s·y(0)-y'(0)=s²·Y(s)

ℒ[y]=Y(s)

ℒ[te^{t}]=\frac{1}{(s-1)^{2}}

So, the transformation is equal to:

s²·Y(s)+Y(s)=\frac{1}{(s-1)^{2}}

(s²+1)·Y(s)=\frac{1}{(s-1)^{2}}

Y(s)=\frac{1}{(s^{2}+1)(s-1)^{2}}

To be able to separate in terms, we use the partial fraction method:

\frac{1}{(s^{2}+1)(s-1)^{2}}=\frac{As+B}{s^{2}+1} +\frac{C}{s-1}+\frac{D}{(s-1)^2}

1=(As+B)(s-1)² + C(s-1)(s²+1)+ D(s²+1)

The equation is reduced to:

1=s³(A+C)+s²(B-2A-C+D)+s(A-2B+C)+(B+D-C)

With the previous equation we can make an equation system of 4 variables.

The system is given by:

A+C=0

B-2A-C+D=0

A-2B+C=0

B+D-C=1

The solution of the system is:

A=1/2 ; B=0 ; C=-1/2 ; D=1/2

Therefore, Y(s) is equal to:

Y(s)=\frac{s}{2(s^{2} +1)} -\frac{1}{2(s-1)} +\frac{1}{2(s-1)^{2}}

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[\frac{s}{2(s^{2} +1)}]-ℒ⁻¹[\frac{1}{2(s-1)}]+ℒ⁻¹[\frac{1}{2(s-1)^{2}}]

y(t)=\frac{1}{2}cos(t)- \frac{1}{2}e^{t}+\frac{t}{2} e^{t}

8 0
3 years ago
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