118 handle bars tells us that there's 118 bikes
if all 118 bikes were regular bikes
118*2 = 236
we would be 33 wheels short
118*1 = 118
we would be 17 seats short
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if 101 of the bikes are regular and 17 are tandem
101*1 = 101
17*2 = 34
we would have the right amount of seats
101*2 = 202
17*2 = 34
202 + 34 = 236
we would be 33 wheels short.
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if 17 bikes are tandem, 33 are tricycle, and 68 are regular
17*2 = 34
33*3 = 99
68*2 = 136
we would have the right amount of wheels
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Answer:
There are 68 bicycles, 17 tandem bicycles, and 33 tricycles.
This question isn't hard, it just takes longer since it's based off of guess and check.
To figure out you would first find a common factor with would be 12. After that 1/4 would be 3/12, 1/3 would be 4/12 and 1/6 would be 2/12. Next you just add all the numbers and get 9/12 then the remainder is you answer which comes to be 3/12 or 1/4. Hope that helps:)
2x^2 + 28x + 98 =
2(x^2 + 14x + 49) =
2(x + 7)(x + 7) <==
Answer:
-3
Step-by-step explanation:
f(x)=-2x+7
f(5)=-2×5+7
=-10+7
=-3
The answer is c i’m pretty sure
