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Simora [160]
3 years ago
11

The equation of a vertical line has what format

Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0
X=_________
or 
y=_________
Most likely it will be x=s.
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I need help with all the problems in this photo I need help now
NeX [460]
The answer to 6 is repeating I believe
5 0
3 years ago
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Line j passes through points 1,6 and 7,1 line k is parallel to line j. What is the slope of line k?
Mashutka [201]
Slope formula m = (y2-y1) / (x2 - x1)
m = (1 - 6) / 7 - 1)
m = -5 / 6

Slope or parallel lines are the same
Slope = -5/6
6 0
3 years ago
Given the equation, what is the center and radius of the circle? <br> (X-2) ^2+ (Y+11)^2=100
LekaFEV [45]

Answer:

Center: (2, -11)

Radius: 10

Step-by-step explanation:

(x - 2)² + (y + 11)² = 100

(x - h)² + (y - k)² = r²

-------------------------------

x - 2 = 0

  +2   +2

x = 2

------------

y + 11 = 0

   -11    -11

y = -11

------------------------------

r² = 100

r = √100

r = 10

----------------------------

Center: (h, k)

Radius: r

-------------------------------

Center: (2, -11)

Radius: 10

I hope this helps!

3 0
2 years ago
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How do you find the length of arc and area of sector
timofeeve [1]
To do this I must first determine what fraction of the circle is represented by the central angle 30°. Since there are 360° in a full circle, I can find the fraction of a circle by simplifying . The sector<span> represents of the circle. To find the </span>arc length<span>, I now need to find the circumference of the entire circle.

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6 0
3 years ago
A bacterial culture starts with 400 bacteria and grows at a rate proportional to its size. After 2 hours there will be 800 bacte
kotykmax [81]

Answer:

  1. P(t) = 400×2^(t/2)
  2. 6400
  3. 5.0

Step-by-step explanation:

The wording "a rate proportional to its size" is an indication that growth (or decay) is exponential.

1) For many problems involving exponential growth, I like to use the numbers given in the problem statement as follows.

  population = (initial population) × (growth factor)^(t/(growth period))

where the "growth period" is the period of time in which the population is multiplied by the "growth factor".

Here, we're given ...

  (initial population) = 400

  (growth factor) = 800/400 = 2

  (growth period) = 2 . . . . hours

So, our population function can be written as ...

  P(t) = 400×2^(t/2)

__

2) Putting t=8 into the formula, we get ...

  P(8) = 400×2^(8/2) = 400×16 = 6400

After 8 hours, the population will be 6400.

__

3) Fill in the given number and solve for t.

  2270 = 400×2^(t/2)

  2270/400 = 2^(t/2)

Taking logs, we have ...

  log(227/40) = (t/2)log(2)

  t = 2×log(227/40)/log(2) ≈ 5.009

After 5.0 hours, the population will reach 2270.

7 0
4 years ago
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