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Natasha_Volkova [10]
3 years ago
6

CAN SOMEONE HELP???????????

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

g(-1) = -1

g(-0.25) = 0

g(2) = 2

Step-by-step explanation:

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What is value of (4g+h)(8)? G(x)= x+7; h(x)= (x-3)^2
babymother [125]

Answer:

85

Step-by-step explanation:

hello :

if : g(x)= x+7; h(x)= (x-3)²   so : (4g+h)(x)=4g(x)+h(x)  = 4(x+7)+(x-3)²  

(4g+h)(8)=  4(8+7)+(8-3)²  = 60+25=85

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3 years ago
Carlotta asks 30 campers which outdoor activity they enjoy. Of these campers, 13 enjoyed swimming, 17 enjoy baseball, and 8 enjo
IgorC [24]
17+13=30-8=22
I did 17 plus 13 which equals 30, then I took 30 and subtracted 8 which equals 22!!!
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3 years ago
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How do you figure out how many days they will once again be at opposition with one another?
MissTica
You will need to find a common multiple of the two. For example:

2: 2, 4, 6
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Whiiz
3 0
3 years ago
Please answer as soon as you can.
madam [21]
Ratio is 4 please like!
6 0
3 years ago
For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at
GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}

Now, let's add the components of the same direction:

\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}

To find the resultant bearing (theta), we can use the formula below:

\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0
1 year ago
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