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gregori [183]
3 years ago
5

Please help me I will fail this test if I don't get this done

Mathematics
1 answer:
ddd [48]3 years ago
5 0
What’s the question?????
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Ed counts 23 black cars, 9 red cars, 17 blue cars, 25 white cars and 21 silver cars during 20 minutes of watching. How many more
amid [387]
23 black cars
9 red cars
17 blue cars
25 white cars
21 silver cars

(white cars + blue cars) - (sliver cars + red cars)
(25 + 17) - (21 + 9)
(42) - (30)
12 more blue and white cars
7 0
3 years ago
5
Sloan [31]
I do not know what question you asked..
5 0
2 years ago
Read 2 more answers
Add the fractions. Write your answer as a mixed number 3/5+4/5
g100num [7]

Answer:

Step-by-step explanation:

3 + 4 = 7.

the denominator stays the same. You only add the numerators.

7/5 in mixed number form is 1  2/5  because 7 goes into 5 once. so kinda like 7 - 5 = 2.  and the 2 goes on top now.

7 0
2 years ago
N^2+16n+60 over 36-n^2
svetoff [14.1K]
Factor
36-n^2 is difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
6^2-n^2=(6-n)(6+n)
factor

n^2+16n+60
find what 2 numbers multiply to 60 and add to 16
factors of 60=2,2,3,5
the numbers are 10 and 6
so factored out
(x+6)(x+10)
(x+6)=(6+x)

so the equation is
[(x+6)(x+10)]/[(6+x)(6-x)]=[(6+x)/(6+x)] times (x+10)/((6-x)=1 times (x+10)/(6-x)


the answer is (x+10)/(6-x)

5 0
3 years ago
the second angel im a triangle is 2° less the 3 times the first angle the third Angle is 14° more than twice the first angle fin
soldier1979 [14.2K]
Let's say the angles are "a", "b" and "c"

\bf \begin{cases}
\stackrel{first}{a}\\
\stackrel{second}{b}=\stackrel{\textit{2 less than 3 times \underline{a}}}{3a-2}\\
\stackrel{third}{c}=\stackrel{\textit{14 more than twice \underline{a}}}{2a+14}
\end{cases}
\\\\\\
\textit{now, the sum of all internal angles in a triangle is }180^o
\\\\\\
a+b+c=\implies a+(3a-2)+(2a+14)=180
\\\\\\
6a+12=180\implies 6a=180-12\implies 6a=168\implies a=\cfrac{168}{6}
\\\\\\
a=28


so a = 28°, plug that in "b" and "c", to see how much each is.
8 0
3 years ago
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