1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luba_88 [7]
3 years ago
5

THERE ARE 6 BOOKS ON A READING LIST. STUDENTS MUST READ ANY 3 OF THE BOOKS ON THE LIST. IN HOW MANY WAYS CAN A STUDENT SELECT AN

Y 3 BOOKS?
Mathematics
1 answer:
aksik [14]3 years ago
3 0
To solve this problem, you must use the Combination Formula:
 
 Cr(n,r)=n! /r!(n-r)!
 
 n: The number of things it can be chosen (n=6).
 r: The number of things you choose (r=3).
 !: The symbol of The Factorial Function, which means that descending numbers are multiplied.
 
 In Combinations the order of the objects does not matter, so we have:
 
 Cr(n,r)=n!/r!(n-r)!
 C(6,3)=6!/3!(6-3)!
 C(6,3)=6!/3!
 C(6,3)= 6x5x4x3!/3x2x1x3!
 C(6,3)=6x5x4/3x2x1
 C(6,3)=120/6
 C(6,3)=20
 
 In how many ways can a student select any 3 books? 
The answer is: In 20 different ways. 
You might be interested in
Free coins- 1) what is 2+2?
Strike441 [17]

Answer:

mean

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
-1/2 w -3/5= 1/5w<br><br> W=
Vinil7 [7]
The exact form is: w = -6/7
8 0
3 years ago
Any portion of the circumference of a circle is called a(n)
Alex777 [14]
Any portion of the circumference of a circle is called a radius
5 0
3 years ago
Consider the ratio 3:5. Can you create an equivalent ratio by adding the same number to each quantity in the ratio? Explain
iragen [17]
Yes because the unit rate would be 1:2 and that's the rate of change in which 3:5 has.
HOPE IT HELPS!!
4 0
3 years ago
Read 2 more answers
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
Other questions:
  • How do you write680,705 in expanded form
    13·1 answer
  • This is geometry, I need help! Please and thanks!!
    15·1 answer
  • Is my answer correct and how do you know? I just graphed it , is there another way I could do it?
    9·2 answers
  • Mr. Andropolis wanted to leave the waiter a 12% tip at the restaurant where he ate lunch. If his bill came to $32.46, how much m
    11·1 answer
  • ?????? Which one? ???!
    10·2 answers
  • For the equation (2x - 2) (4x +4)
    11·1 answer
  • Learn with an example
    15·1 answer
  • Estimate a 20% tip on a dinner bill of \$173.26 by first rounding the bill amount to the nearest ten dollars .
    15·2 answers
  • Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
    6·1 answer
  • Work out the area of the trapezium ABDE.<br> A<br> В.<br> 7.5 cm<br> 2.5 cm<br> С<br> 5 cm<br> E
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!