Answer:
man just try to get the answer right yourself
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
Learn more about algebra:
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Answer:
Step-by-step explanation:
(5x+1)²>(2x+2)²+(4x)²
25x²+10x+1>4x²+8x+4+16x²
5x²+2x-3>0
5x²+5x-3x-3>0
5x(x+1)-3(x+1)>0
(x+1)(5x-3)>0
x+1=0,gives x=-1
5x-3=0,gives x=3/5
x >0(because 4x should be >0)
side is always positive.
so x>3/5
again 5x+1<2x+2+4x
5x-6x<2-1
-x<1
x>-1
x=all real values >3/5
